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The difference between the squares of two positive integers is 2011 wh

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New post 12 Nov 2019, 02:33
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The difference between the squares of two positive integers is 2011 what is the greatest possible sum of those two integers?

A. 1002
B. 1005
C. 1007
D. 1809
E. None of these


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The difference between the squares of two positive integers is 2011 wh  [#permalink]

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New post 12 Nov 2019, 05:21
Bunuel wrote:
The difference between the squares of two positive integers is 2011 what is the greatest possible sum of those two integers?

A. 1002
B. 1005
C. 1007
D. 1809
E. None of these


Are You Up For the Challenge: 700 Level Questions


Let the two numbers be a and b, so \(a^2-b^2=2011....(a-b)(a+b)=1*2011\)
\(a-b=1\) and \(a+b=2011\)...
Straight a+b=2011
OR
Add to get 2a=1+2011...a=1006 and b, therefore,=1005
\(SUM=1005+1006\)

E
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Re: The difference between the squares of two positive integers is 2011 wh  [#permalink]

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New post 20 Nov 2019, 19:14
Bunuel wrote:
The difference between the squares of two positive integers is 2011 what is the greatest possible sum of those two integers?

A. 1002
B. 1005
C. 1007
D. 1809
E. None of these


Are You Up For the Challenge: 700 Level Questions


We can create the equation:

a^2 - b^2 = 2011

(a + b)(a - b) = 2011

Since 2011 is a prime, we see that a + b = 2011 and a - b = 1. We see that the sum of the two integers must be 2011.

Answer: E
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Re: The difference between the squares of two positive integers is 2011 wh  [#permalink]

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New post 24 Nov 2019, 21:05

Solution


Given:
    • The difference between the squares of two positive integers = 2011

To find:
    • The greatest possible sum of those two integers

Approach and Working Out:
    • Given, \(a^2 – b^2 = 2011\)
      o Implies, (a + b) * (a – b) = 2011

    • We know that 2011 is a prime number, so it can be expressed as product of two positive integers in only one way = 1 * 2011
    • Thus, a + b = 2011

Hence, the correct answer is Option E.

Answer: E
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Re: The difference between the squares of two positive integers is 2011 wh   [#permalink] 24 Nov 2019, 21:05
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