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caimanoliveira
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caimanoliveira
The distance between –𝟐/5 and X is 𝟐/3 of the distance between – 𝟐/5
and 𝟏/2 . In which point of the axis is X situated?

a)0.2
b)0.3
c)0.45
d)0.48
e)7/18

-2/5--------------------0-------2/10----------1/2-------------------1

The distance between \(-\frac{2}{5}\) and \(\frac{1}{2}\) = \(\frac{1}{2} + \frac{2}{5} = \frac{9}{10}\)


since both lengths start with \(-\frac{2}{5}\), we can subtract one-third of the length instead which is \(\frac{3}{10}\).

\(\frac{1}{2} - \frac{3}{10} = \frac{2}{10} = 0.2\).


Ans: A
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Given: Distance between –2/5 and X = 2/3 * distance between – 2/5 and 1/2.

To find: X

Solution:
Distance between -2/5 and 1/2 = 1/2 - (-2/5)
= 1/2 + 2/5
= 5/10 + 4/10
= 9/10


So, distance between -2/5 and X = 2/3 * (9/10) = 3/5

Now, X could be -2/5 - 3/5 OR -2/5 + 3/5.


Since all choices ae positive, we will take X = -2/5 + 3/5 = 1/5 = 0.2


Correct Answer: A


Shweta Koshija
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