GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 23 Jan 2019, 00:11

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in January
PrevNext
SuMoTuWeThFrSa
303112345
6789101112
13141516171819
20212223242526
272829303112
Open Detailed Calendar
• ### Key Strategies to Master GMAT SC

January 26, 2019

January 26, 2019

07:00 AM PST

09:00 AM PST

Attend this webinar to learn how to leverage Meaning and Logic to solve the most challenging Sentence Correction Questions.
• ### Free GMAT Number Properties Webinar

January 27, 2019

January 27, 2019

07:00 AM PST

09:00 AM PST

Attend this webinar to learn a structured approach to solve 700+ Number Properties question in less than 2 minutes.

# The figure above shows a circle inscribed in a square which is in turn

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 52412
The figure above shows a circle inscribed in a square which is in turn  [#permalink]

### Show Tags

31 Oct 2018, 00:37
00:00

Difficulty:

25% (medium)

Question Stats:

72% (01:44) correct 28% (01:02) wrong based on 65 sessions

### HideShow timer Statistics

The figure above shows a circle inscribed in a square which is in turn inscribed within a larger circle. What is the ratio of the area of the larger circle to that of the smaller circle?

A. √2

B. π/2

C. π^2/(4√2)

D. 2

E. π/√2

Attachment:

phd01.png [ 13.19 KiB | Viewed 479 times ]

_________________
Manager
Joined: 09 Jun 2018
Posts: 187
Location: United States
GPA: 3.95
WE: Manufacturing and Production (Energy and Utilities)
Re: The figure above shows a circle inscribed in a square which is in turn  [#permalink]

### Show Tags

31 Oct 2018, 06:27
Half of diagonal of square = sqrt(r^2 + r^2) = $$\sqrt{2}$$r = Radius of larger circle

Ratio = pi*$$(sqrt(2)r)^2$$/pi*$$r^2$$ = 2

Option D
_________________

If you found this relevant and useful, please Smash that Kudos button!

Intern
Joined: 06 Oct 2017
Posts: 36
GPA: 3.6
Re: The figure above shows a circle inscribed in a square which is in turn  [#permalink]

### Show Tags

20 Nov 2018, 13:49
nkin wrote:
Half of diagonal of square = sqrt(r^2 + r^2) = $$\sqrt{2}$$r = Radius of larger circle

Ratio = pi*$$(sqrt(2)r)^2$$/pi*$$r^2$$ = 2

Option D

I'm a little lost. I thought the diagonal of a square was d=s√2 so wouldn't d=s√2/2 be the radius of the larger circle ? Where did you get sqrt(r^2 + r^2)
Re: The figure above shows a circle inscribed in a square which is in turn &nbs [#permalink] 20 Nov 2018, 13:49
Display posts from previous: Sort by