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15 Dec 2014, 09:00
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D
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The figure above shows the dimensions of a square picture frame that was constructed using four identical pieces of frame as shown. If w is the width of each piece of the frame, what is the area of the front surface of each piece? (1 ft = 12 inches)
(1) w = 3 inches
(2) PQ = \(\sqrt{18}\) inches
DS87602.01
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2007-01-02_114321_z.jpg [ 3.01 KiB | Viewed 22500 times ]
16 Dec 2014, 02:20
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Statement A: Sufficient: By knowing the value of w, we can know the area of the inner square (3ft-2w is the length of inner square). and by subtracting the inner square area from the outer square area, we can know the area of the frame.
Statement B: Sufficient: we can find out the diagonal value out the square, and using the value of this statement, we can get the diagonal value of inner square and its area. subtract the inner square area from the outer square area.
Need not get the exact value of the area of the frame.
Answer:D
Statement B: Sufficient: we can find out the diagonal value out the square, and using the value of this statement, we can get the diagonal value of inner square and its area. subtract the inner square area from the outer square area.
Need not get the exact value of the area of the frame.
Answer:D
16 Dec 2014, 01:23
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I think the answer is D.
Area of each piece S= (3ft*3ft-(3f-w)*(3ft-w))/4
Statement 1: w=3inch => we can calculate S. Suff
Statement 2: We know PQ and PQ is hypotenuse of a right isolece triangle w, we can calculate w => we can calculate S. Suff
Area of each piece S= (3ft*3ft-(3f-w)*(3ft-w))/4
Statement 1: w=3inch => we can calculate S. Suff
Statement 2: We know PQ and PQ is hypotenuse of a right isolece triangle w, we can calculate w => we can calculate S. Suff
