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eybrj2

The figure above shows the shape and dimensions of the inside of a container that has a flat rectangular top and semicircular ends perpendicular to the top. When the container is loaded to its exact capacity with slag that weighs 50 pounds per cubic foot, what will be the approximate weight, in tons, of the slag in the container?
(1 ton = 2000 pounds)

A. 2
B. 4
C. 6
D. 8
E. 10

Solution:

We see that the container is a “semi-cylinder;”; therefore, its volume is ½ x π x 4^2 x 10 = 80π cubic feet. Since the slag weighs 50 pounds per cubic foot, the slag in the container weighs 50 x 80π = 4000π pounds. Since 1 ton = 2000 pounds, the slag weighs 4000π/2000 = 2π tons, or approximately 6 tons (recall that π is approximately 3.14).

Answer: C
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Can we solve this using a rectangle and 2 semi circles??

GMATNinja

How to solve this without a formula??
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Can we solve this using a rectangle and 2 semi circles??

GMATNinja

How to solve this without a formula??
The easiest way to solve this one is to use the formula for the volume of a cylinder, and to then chop the volume in half.

To remember the formula, think of an empty, cylindrical water glass sitting on a table. If you were to fill up the glass with water from a jug, the water would first spread out to cover the entire bottom area of the of the glass. That base area would be \(\pi r^2\). Then, as you continue to pour water in, the water level would rise up the height of the glass. So, for overall volume of a cylinder, you end up with \(\pi r^2h\).

Because this cylinder is chopped in half, the volume of the container will be \(\frac{1}{2}\pi r^2h\).

I hope that helps!
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