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The figure shows a square patio surrounded by a walkway of width x

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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 20 Jul 2015, 04:15
width of the walkway = x
width of the small square = x+5 = x+5
width of the whole large square = x+5+x+x = 3x+5

Difference between area
(3x+5)^2 - (x+5)^2 = 132
8x^2 +20x = 132
4x(2x+5) = 132
x (2x+5) = 33 = 3*11
Hence, x = 3
x+5 = 8
8^2 = 64
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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 14 Oct 2015, 07:23
Engr2012 wrote:
PathFinder007 wrote:
amitdgr wrote:
The figure shows a square patio surrounded by a walkway of width x meters. If the area of the walkway is 132 square meters and the width of the patio is 5 meters greater than the width of the walkway, what is the area of the patio, in square meters?

A. 56
B. 64
C. 68
D. 81
E. 100



Hi bunuel,

Could you please provide your comments on how we are getting 5+3x.

i didnt get it.

Thanks.


It is given that width of the patio is 5 more than width of the walkway. Now, walkway's 'extension on either side of the patio' is 'x' and thus width of the of the patio = \(W_P\) = 5+x

Now, total width of the walkway = \(W_W\) = width of the patio + 2*x = 5+x+2x = 5+3x

it requires a redesign figure, which is not provided by anyone, only for this reason many confusion arise, could you please make a understandable figure please?
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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 22 Oct 2016, 05:20
(3x+5)^2 - (x+5)^2 = 132

Solving for x = 64

Hence B
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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 19 Jul 2017, 00:11
I eventually didn't understand the figure . The outer box is the walkway and the inner one is the patio. Am i correct? Sorry seems like silly question, but iam weak in geometry and it would really great if someone could help me understand the figure.
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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 19 Jul 2017, 01:03
longhaul123 wrote:
I eventually didn't understand the figure . The outer box is the walkway and the inner one is the patio. Am i correct? Sorry seems like silly question, but iam weak in geometry and it would really great if someone could help me understand the figure.


We are given that the patio is surrounded by a walkway, so yellow area is walkway and red is patio itself.
Attachment:
patio.JPG
patio.JPG [ 13.39 KiB | Viewed 727 times ]

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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 19 Jul 2017, 23:01
Thank youBunuel
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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 20 Jul 2017, 02:49
I did not realise this when I first read the question but with hindsight the fastest way to solve this is to realise that:

both the answer and answer+132 must be perfect squares so:

A) 56 not a square
B) 64 is ok and 64+132 =196 is also ok
C) 58 not a square
D) 81+132 = 213 not a square
E) 100+132 = 232 not a square

so answer is C
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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 25 Jul 2017, 11:14
1
rthothad wrote:
Image
The figure shows a square patio surrounded by a walkway of width x meters. If the area of the walkway is 132 square meters and the width of the patio is 5 meters greater than the width of the walkway, what is the area of the patio, in square meters?

A. 56
B. 64
C. 68
D. 81
E. 100


If we let x = the width of the walkway, then the width of the patio = x + 5. Let’s create the equation for the area of the combined walkway and patio. We see that the entire length of the combined walkway-patio is (x + x + x + 5) = (3x + 5). Because it is a square, we square (3x + 5) to determine the combined area. We see that this is equal to the area of the patio plus the area of the walkway:

(3x + 5)^2 = (x + 5)^2 + 132

9x^3 + 30x + 25 = x^2 + 10x + 25 + 132

8x^2 + 20x - 132 = 0

2x^2 + 5x - 33 = 0

(2x + 11)(x - 3) = 0

2x + 11 = 0

2x = -11

x = -5.5

Or x = 3

Since x cannot be negative, x = 3.

Since x = 3, the area of the patio is (3 + 5)^2 = 8^2 = 64.

Answer: B
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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 07 Aug 2019, 22:39
rthothad wrote:
Image
The figure shows a square patio surrounded by a walkway of width x meters. If the area of the walkway is 132 square meters and the width of the patio is 5 meters greater than the width of the walkway, what is the area of the patio, in square meters?

A. 56
B. 64
C. 68
D. 81
E. 100

Attachment:
patio.JPG


Leave everything else.
If I have to add something to 132 the result should be a perfect square. Option B works. :)
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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 07 Aug 2019, 23:50
Since it is a square the area should be a perfect square.

Area given 132

Option b 64

Total area 64+132=196

Side =14

Only this option has a perfect square

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Re: The figure shows a square patio surrounded by a walkway of width x  [#permalink]

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New post 08 Aug 2019, 00:09
Ans 64. Attached solution

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IMG_20190808_123756099.jpg [ 2.43 MiB | Viewed 40 times ]

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Re: The figure shows a square patio surrounded by a walkway of width x   [#permalink] 08 Aug 2019, 00:09

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