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Arick
f(x) = -x²+6x+20

The function f is defined above. Which of the following equivalent forms of f(x) displays the maximum value of f as a constant or coefficient?

(A) f(x) = (x-3)²+11

(B) f(x) = -(x-3)²+29

(C) f(x) = -(x+3)² + 11

(D) f(x) = (x+3)² +29

(E) f(x) = -(x-3)²-11

Posted from my mobile device

I didnt quite understand the qs. Can someone pls help?
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Arick
f(x) = -x²+6x+20

The function f is defined above. Which of the following equivalent forms of f(x) displays the maximum value of f as a constant or coefficient?

(A) f(x) = (x-3)²+11

(B) f(x) = -(x-3)²+29

(C) f(x) = -(x+3)² + 11

(D) f(x) = (x+3)² +29

(E) f(x) = -(x-3)²-11

Posted from my mobile device

I didnt quite understand the qs. Can someone pls help?


The question wants us to convert the given equation in a form in which the MAX value of the function is visible .

But we don't know what is the MAX value. To find that we have to convert the existing equation in some (a+b)^2 or (a-b)^2 form as shown below:

f(x) = -x²+6x+20
f(x) = -x²+6x-9+29
f(x) = -(x²-6x+9)+29
f(x) = -(x-3)²+29 --> Now we can see this will give max value when the constant (29) is not subtracted by any number . The MAX value is 29.
We see that this equation already has the max value in it. So this is our required answer.

Correct Option - (B)
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Step 1: Choosing a Test Value
A quick way to identify the correct answer in a multiple-choice setting is to substitute a test value into the original function and compare the results with the given options.

Let's choose x=1x=1 as our test value and compute f(1)
:

f(1)=−(1)^2+6(1)+20 = −1+6+20 = 25

Step 2: Evaluating Each Answer Choice
Now, we check which option gives f(1)=25

  • (A) (1−3)^2+11=(−2)^2+11=4+11=15 ❌
  • (B) −(1−3)^2+29=−4+29 = 25 ✅
  • (C) −(1+3)^2+11=−(4)^2+11=−16+11=−5 ❌
  • (D) (1+3)^2+29=(4)^2+29=16+29=45 ❌
  • (E) −(1−3)^2−11=−4−11=−15 ❌
The only correct answer is (B), as it produces the expected result.

PS : You can do with all numbers and get only one good answer except 0 in which you will have A and B good but we need to find the value that maximise so B will be right answer.
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