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Answer = C = 12

\(Product = 1 * 2 * -2 * -3 = 12\)
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Official Solution:

The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\), while the function \(h(x)\) is defined as the least integer greater than or equal to \(x\). What is the product \(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3)\)?

A. 6
B. 9
C. 12
D. 16
E. 24

In problems involving "decimal functions," which involve rounding decimals up or down to a nearby integer, we must be very careful to follow directions precisely. Here, we have two functions that have similar but distinct definitions.

To avoid confusion between the two functions, evaluate just one function's results first.

The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\). So \(g(1.7) = 1\), while \(g(-1.7) = -2\). Notice how this function operates on negative numbers. The results are not symmetrical: \(g(-1.7)\) does not equal the negative of \(g(1.7)\).

Likewise, we have the function \(h(x)\) defined as the least integer greater than or equal to \(x\). So \(h(2.3) = 3\), while \(h(-2.3) = -2\). Again, the results are not symmetrical: \(h(-2.3)\) does not equal the negative of \(h(2.3)\).

Now we multiply the results together:
\(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3) = 1 \times 3 \times (-2) \times (-2) = 12.\)

Answer: C.
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Bunuel
Official Solution:

The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\), while the function \(h(x)\) is defined as the least integer greater than or equal to \(x\). What is the product \(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3)\)?

A. 6
B. 9
C. 12
D. 16
E. 24

In problems involving "decimal functions," which involve rounding decimals up or down to a nearby integer, we must be very careful to follow directions precisely. Here, we have two functions that have similar but distinct definitions.

To avoid confusion between the two functions, evaluate just one function's results first.

The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\). So \(g(1.7) = 1\), while \(g(-1.7) = -2\). Notice how this function operates on negative numbers. The results are not symmetrical: \(g(-1.7)\) does not equal the negative of \(g(1.7)\).

Likewise, we have the function \(h(x)\) defined as the least integer greater than or equal to \(x\). So \(h(2.3) = 3\), while \(h(-2.3) = -2\). Again, the results are not symmetrical: \(h(-2.3)\) does not equal the negative of \(h(2.3)\).

Now we multiply the results together:
\(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3) = 1 \times 3 \times (-2) \times (-2) = 12.\)

Answer: C.

Check other Rounding Functions Questions in our Special Questions Directory.

Hope it helps.
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Bunuel

Tough and Tricky questions: Number Properties.



The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\), while the function \(h(x)\) is defined as the least integer greater than or equal to \(x\). What is the product \(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3)\)?

A. 6
B. 9
C. 12
D. 16
E. 24

Kudos for a correct solution.

g(1.7) = 1
h(2.3) = 3
g(-1.7) = -2
h(-2.3) = -2

product = 12
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Bunuel

Tough and Tricky questions: Number Properties.



The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\), while the function \(h(x)\) is defined as the least integer greater than or equal to \(x\). What is the product \(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3)\)?

A. 6
B. 9
C. 12
D. 16
E. 24

Kudos for a correct solution.


Let's first get a better idea of what each function does.

g(x) = the greatest integer less than or equal to x
So, for example, g(3.1) = 3, since 3 is the greatest integer that is less than 3.1
Likewise, g(8.7) = 8, since 8 is the greatest integer that is less than 8.7
And g(4.2) = 4, f(0.5) = 0 and f(-5.55) = -6

h(x) = the least integer greater than or equal to x
So, for example, h(4.6) = 5, since 5 is the smallest integer that is greater than 4.6
Likewise, h(10.11) = 11, since 11 is the smallest integer that is greater than 10.11
And h(0.4) = 1, h(-2.33) = -2 and h(-3.5) =-3

So.... [g(1.7)][h(2.3)][g(-1.7)][h(-2.3)] = (1)(3)(-2)(-2) = 12

Answer: C

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the product g(1.7)×h(2.3)×g(−1.7)×h(−2.3)

=> 1*3*(-2)*(-2) = 12

Option C
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Official Solution:

The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\), while the function \(h(x)\) is defined as the least integer greater than or equal to \(x\). What is the product \(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3)\)?

A. 6
B. 9
C. 12
D. 16
E. 24

In problems involving "decimal functions," which involve rounding decimals up or down to a nearby integer, we must be very careful to follow directions precisely. Here, we have two functions that have similar but distinct definitions.

To avoid confusion between the two functions, evaluate just one function's results first.



The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\). So \(g(1.7) = 1\), while \(g(-1.7) = -2\). Notice how this function operates on negative numbers. The results are not symmetrical: \(g(-1.7)\) does not equal the negative of \(g(1.7)\).

Likewise, we have the function \(h(x)\) defined as the least integer greater than or equal to \(x\). So \(h(2.3) = 3\), while \(h(-2.3) = -2\). Again, the results are not symmetrical: \(h(-2.3)\) does not equal the negative of \(h(2.3)\).

Now we multiply the results together:
\(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3) = 1 \times 3 \times (-2) \times (-2) = 12.\)

Answer: C.


Please help me understand why is g(1.7) 1 and not 2? Similarly how is g(-1.7) -2?
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Bunuel
Official Solution:

The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\), while the function \(h(x)\) is defined as the least integer greater than or equal to \(x\). What is the product \(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3)\)?

A. 6
B. 9
C. 12
D. 16
E. 24

In problems involving "decimal functions," which involve rounding decimals up or down to a nearby integer, we must be very careful to follow directions precisely. Here, we have two functions that have similar but distinct definitions.

To avoid confusion between the two functions, evaluate just one function's results first.



The function \(g(x)\) is defined as the greatest integer less than or equal to \(x\). So \(g(1.7) = 1\), while \(g(-1.7) = -2\). Notice how this function operates on negative numbers. The results are not symmetrical: \(g(-1.7)\) does not equal the negative of \(g(1.7)\).

Likewise, we have the function \(h(x)\) defined as the least integer greater than or equal to \(x\). So \(h(2.3) = 3\), while \(h(-2.3) = -2\). Again, the results are not symmetrical: \(h(-2.3)\) does not equal the negative of \(h(2.3)\).

Now we multiply the results together:
\(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3) = 1 \times 3 \times (-2) \times (-2) = 12.\)

Answer: C.


Please help me understand why is g(1.7) 1 and not 2? Similarly how is g(-1.7) -2?


The function g rounds DOWN a number to the nearest integer. For example [1.5]=1 (because 1 is the greatest integer less than or equal to 1.5), [2]=2, [-1.5]=-2, ...


The function h rounds UP a number to the nearest integer. For example [1.5]=2 (because 2 the least integer greater than or equal to 1.5), [2]=2, [-1.5]=-1, ...

Check other Rounding Functions Questions in our Special Questions Directory.

Hope it helps.
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Given that g(x) = the greatest integer less than or equal to \(x\) and h(x) = the least integer greater than or equal to x and we need to find the value of \(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3)\)

g(1.7) = the greatest integer less than or equal to 1.7 = 1
h(2.3) = the least integer greater than or equal to 2.3 = 3
g(-1.7) = the greatest integer less than or equal to -1.7 = -2
h(-2.3) = the least integer greater than or equal to -2.3 = -2

=> \(g(1.7) \times h(2.3) \times g(-1.7) \times h(-2.3)\) = \(1 \times 3 \times -2 \times -2\) = 3*4 = 12

So, Answer will be C
Hope it helps!

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