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Bunuel
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Ans : A

z= a+(a+1)+(a+2)...

when a=2, n=1 ; z= a/n and z is divisible by n
when a= 2, n=2 ; z= (a+(a+1))/2 ie Z=5/2 .... so z is not divisible by n
when a=2, n=3 ; z=(2+3+4) /3 ie z=9/3 .... so Z is divisible by n
when a=3, n=2 ; z is not divisible by n
when a=3, n=3; Z is divisible by n
a=even, N=even ; z is not divisible by n
a= even, N= Odd ; z is divisible by n
a= ODD , N= Odd ; z is divisible by n
a= odd, N = even; z is not divisible by n

any value of a, N should be odd... for z is divisible by n

1) => n is not an even no. ie, n=1,3,5,.... (n=odd)
sufficient

2)=> a is an even no. ie, a=2,4,6
n=1,2,3,4,5,...

not sufficient
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Can someone solve this question with the function SCI(8,5) which would mean=
8+9+10+11+12=30 and is also divisible by 5 which is n.

Is there anything I'm not seeing or should the answer be E?nick1816
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SCI(8,3)= 27(divisible by 3 or n)

SCI(8,4)= 38(not divisible by 4 or n)

SCI(8,5)= 50 (divisible by 5 or n)

SCI(8,6) = 63(not divisible by 6 or n)

SCI(8,7)= 77(divisible by 7 or n)

SCI(8,8)= 82(not divisible by 8 or n)

You can notice the pattern that when n is odd, SCI(a,n) is divisible by n and when n is even, SCI(a,n) is not divisible by n.

Statement 1 tells you that n is odd; hence SCI(a,n) must be divisible by n.

Sufficient



merttural11
Can someone solve this question with the function SCI(8,5) which would mean=
8+9+10+11+12=30 and is also divisible by 5 which is n.

Is there anything I'm not seeing or should the answer be E?nick1816
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