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The graph of the equation xy = k, where k < 0, lies in which two of th
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15 Oct 2015, 21:01
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The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment:
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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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15 Oct 2015, 23:12
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: 20151016_0900.png My Solution:
If k < 0 then the product of x and y = k
It is only possible when either x or y is negative.
If x is negative and y positive (x,y) = Quadrant II
If x is positive and y negative (x,y) = Quadrant IV
Answer D
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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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15 Oct 2015, 22:41
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: 20151016_0900.png y=k/x (0,0); when x is +ve y will be negative and vice versa > Quadrant 2 and 4 Answer (D)



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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16 Oct 2015, 00:37
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: 20151016_0900.png x, y will be different in SIGN, meaning that x <0, y>0 or x>0, y<0 => Ans: D



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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16 Oct 2015, 01:45
xy = k and k <0 => x< 0 or y <0 So ,the coordinates will have opposite signs . Quadrant 2 : (x , y ) Quadrant 4 : (x,y) Answer D
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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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16 Oct 2015, 07:02
XY=K and K<0 ; so we can say that 1. X is negative y is positive 2. X is positive y is negative 3. neither of them will not be zero
Hence to satisfy above conditions; equation xy<o has to be in 2nd and 4th quadrant where one of them will be positive and another will be negative. Hence answer is D



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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17 Oct 2015, 03:50
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: 20151016_0900.png D  If you the graph of y=1/x then just take the reflection of that curve about the axis to get y=1/x



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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17 Oct 2015, 06:51
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: The attachment 20151016_0900.png is no longer available To answer any such question, the easiest way is to choose the value of unknowns as per the given constraint (e.g. k = 10 or 20 etc.) and then substitute value of one of the variables and calculate the value of other variable as per the given expression (xy=k in this case) and finally plot them to answer the questionPlease refer the figure below with assumed value of k = 10Answer: option D
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The graph of the equation xy = k, where k < 0, lies in which two of th
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13 Feb 2016, 17:34
Can this equation be brought into the y=mx+b form or is it a quadratic. If it can then what is the slope for this equation considering it has two different lines in different quadrants?
Thanks!



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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11 May 2016, 01:03
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: 20151016_0900.png We know xy<0. So x&y will have opposite signs. Now in Q3 & Q1, x&y have equal signs. So only possible placement for line will be out of Q1 and Q4. That means line xy=k will lie on Q3&Q4.So answer is D



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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11 May 2016, 06:22
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: 20151016_0900.png Solution: We are given the equation xy = k, where k is negative. It follows that x and y must have opposite signs. That is, either x is positive and y is negative, which is only possible in Quadrant IV, or, x is negative and y is positive, which is only possible in Quadrant II. Answer: D
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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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14 Jul 2016, 04:51
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: 20151016_0900.png xy=k ==>xy=k+0 y=k/x +0 equation for line is y=mx+b So we know y intercept is 0 which means when x=0, y=0 Meaning the line is passing through the origin (0,0) ==> perfect. Now we need to figure out the slope==> k is the slope==> it is negative (given in question stem)==> line starts in Q II passes through the origin (0,0) and enters Q IV Answer should have Q II and Q IV in it. ANSWER IS D
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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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17 Nov 2016, 08:41
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: 20151016_0900.png here, K=negative xy=k xy=() () (+)=() >which indicates quadrant II (+) ()=() >which indicates quadrant IV So, Correct answer is D



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The graph of the equation xy = k, where k < 0, lies in which two of th
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30 May 2017, 15:11
Attached is a visual that should help. I suggest picking a simple negative number for k, such as 1, to make the concept more clear. Note that the question doesn't say what k equals, so you are allowed to set the value of k to any negative number, and it should still work.
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Screen Shot 20170530 at 4.07.06 PM.png [ 76.29 KiB  Viewed 22332 times ]



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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04 Jun 2017, 00:20
If k < 0 then the product of x and y = k
It is only possible if either x or y is negative.
x is ve & y +ve (x,y) = Quadrant II
Option should be A, C, D
Lets look at point second condition x is +veand y ve (x,y) = Quadrant IV
Ans D



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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30 Jan 2020, 20:11
Please do not overcomplicate the question at hand. We are told that x * y = k and k<0. So x*y<0 meaning that there are two possible combinations:
x * y < 0 when
(1) negative * positive, OR (2) positive * negative
Now it is plain simple: (1) lies in the II quadrant while (2) is in the IV quadrant.



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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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06 Mar 2020, 02:43
Bunuel wrote: The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above? (A) I and II (B) I and III (C) II and III (D) II and IV (E) III and IV Kudos for a correct solution.Attachment: The attachment 20151016_0900.png is no longer available Graphical solution. Since xy < 0, either x or y is negative. Attachment:
xy = k.png [ 41.89 KiB  Viewed 3035 times ]
Answer D.
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Re: The graph of the equation xy = k, where k < 0, lies in which two of th
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06 Mar 2020, 02:43




