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655-705 (Hard)|   Graphs|            
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Official Explanation

By following the gridline at 60°C, the visible line indicating the solubility of \(NaNO_{3}\) is highest on the graph. However, the line for KI extends above the scale shown on the graph. So, given the assumption that the curves continue in the same general shape beyond the plotted area, the information given indicates that KI is the most soluble at 60°C.

The correct answer is KI.

The vertical distance between the solubility curves for KClO3 and NH4Cl decreases as the temperature increases, thus the difference in solubility between KClO3 and NH4Cl decreases as the temperature increases. Assuming that the curves continue in the same general shape beyond the plotted area, the vertical distance between them will eventually be zero, thereby indicating that there is a temperature at which the two chemicals are equally soluble. By contrast, the solubility curves for KCl and NaCl have increasingly greater vertical distances from that of NH4Cl as the temperature increases. Thus the differences in the solubilities of either KCl or NaCl as compared to that of NH4Cl would continue to increase as the temperature increases.

The correct answer is KClO3.
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in the first question how do you know that you can go beyond the graph?
Sajjad1994
Official Explanation

By following the gridline at 60°C, the visible line indicating the solubility of \(NaNO_{3}\) is highest on the graph. However, the line for KI extends above the scale shown on the graph. So, given the assumption that the curves continue in the same general shape beyond the plotted area, the information given indicates that KI is the most soluble at 60°C.

The correct answer is KI.

The vertical distance between the solubility curves for KClO3 and NH4Cl decreases as the temperature increases, thus the difference in solubility between KClO3 and NH4Cl decreases as the temperature increases. Assuming that the curves continue in the same general shape beyond the plotted area, the vertical distance between them will eventually be zero, thereby indicating that there is a temperature at which the two chemicals are equally soluble. By contrast, the solubility curves for KCl and NaCl have increasingly greater vertical distances from that of NH4Cl as the temperature increases. Thus the differences in the solubilities of either KCl or NaCl as compared to that of NH4Cl would continue to increase as the temperature increases.

The correct answer is KClO3.
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Legallyblond
in the first question how do you know that you can go beyond the graph?


Check the question:


Under the assumption that the curves shown continue in the same general shape beyond the plotted area, ...
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Q-1
need to find most soluable chemical at 60
we can just look at for the choice given and see each of their soluable num at 60.
KCI= 45
KI = would be above 170
NANO3= 125
SO0= 5

clearly KI is the one with highest.

Q-2
need to find which other chemical is as soluable as NH4CL at temp above 100.

KCI- this is pretty much flat line and will take very long to meet with given chemical. so out.
KCIO3 = although its bit below nh4cl but it has very steep increment and will likely cross nh4cl at around given temp. so keep.
NACL= no chance for this one. firstly its way below the nh4cl and its pretty much in flat line. so hard to match with nh4cl at any point.

ANS
Q-1 KI
Q-2 KCIO3
parkhydel


The graph shows how the solubility of various chemicals varies with temperature. The solubility is measured as grams of dissolved chemical (solute) per 100 grams of water.

Under the assumption that the curves shown continue in the same general shape beyond the plotted area, use the drop-down menus to complete each of the following statements in the manner that most accurately reflects the information provided.

At 60°C, the most soluble of the chemicals is most likely .

There is most likely a temperature above 100°C at which NH4Cl is exactly as soluble as .
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