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22 Jul 2018, 23:20
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The hexagonal face of the block shown in the figure above has sides of equal length and angles of equal measure. If each lateral face is rectangular, what is the area, in square inches, of one lateral face?
(A) \(2 \sqrt{10}\)
(B) 12
(C) 20
(D) \(12 \sqrt{3}\)
(E) 24
Attachment:
2018-07-23_1017.png [ 10.12 KiB | Viewed 7139 times ]
23 Jul 2018, 02:22
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Bunuel
Equal sides and equal angles means REGULAR hexagon.
If the biggest diagonal is 24 half will be 12 and will meet at the centre of hexagon.
Thus formed is equilateral triangle of side is 12..
So the lateral face has sides 12 and 2, so area is 12*2=24
E
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24 Sep 2025, 03:48
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