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The hexagonal face of the block shown in the figure above has sides

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The hexagonal face of the block shown in the figure above has sides  [#permalink]

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New post 22 Jul 2018, 23:20
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The hexagonal face of the block shown in the figure above has sides of equal length and angles of equal measure. If each lateral face is rectangular, what is the area, in square inches, of one lateral face?


(A) \(2 \sqrt{10}\)

(B) 12

(C) 20

(D) \(12 \sqrt{3}\)

(E) 24


Attachment:
2018-07-23_1017.png
2018-07-23_1017.png [ 10.12 KiB | Viewed 411 times ]

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The hexagonal face of the block shown in the figure above has sides  [#permalink]

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New post 23 Jul 2018, 02:22
Bunuel wrote:
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The hexagonal face of the block shown in the figure above has sides of equal length and angles of equal measure. If each lateral face is rectangular, what is the area, in square inches, of one lateral face?


(A) \(2 \sqrt{10}\)

(B) 12

(C) 20

(D) \(12 \sqrt{3}\)

(E) 24


Attachment:
The attachment 2018-07-23_1017.png is no longer available


Equal sides and equal angles means REGULAR hexagon.
If the biggest diagonal is 24 half will be 12 and will meet at the centre of hexagon.
Thus formed is equilateral triangle of side is 12..

So the lateral face has sides 12 and 2, so area is 12*2=24

E
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The hexagonal face of the block shown in the figure above has sides &nbs [#permalink] 23 Jul 2018, 02:22
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