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Updated on: 26 Nov 2018, 07:20
Originally posted by GMATnavigator on 21 Jul 2015, 10:52.
Last edited by Bunuel on 26 Nov 2018, 07:20, edited 2 times in total.
Last edited by Bunuel on 26 Nov 2018, 07:20, edited 2 times in total.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
59% (02:29) correct
41%
(02:39)
wrong
based on 484
sessions
History
Date
Time
Result
Not Attempted Yet
The length, breadth and height of a room are in the ratio 3:2:1. If the breadth and height are halved while the length is doubled, then the total area of the four walls of the room will
(a) remain the same
(b) decrease by 13.64%
(c) decrease by 15%
(d) decrease by 18.75%
(e) decrease by 30%
Source: Gmat Cat By Nill (Peterson)
(a) remain the same
(b) decrease by 13.64%
(c) decrease by 15%
(d) decrease by 18.75%
(e) decrease by 30%
Source: Gmat Cat By Nill (Peterson)
21 Jul 2015, 22:33
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GMATnavigator
The length, breadth and height of a room are in the ratio 3 : 2 : 1. If the breadth and height are halved while the length is doubled, then the total area of the four walls of the room will
(a) remain the same
(b) decrease by 13.64%
(c) decrease by 15%
(d) decrease by 18.75%
(e) decrease by 30%
Source: Gmat Cat By Nill (Peterson)
(a) remain the same
(b) decrease by 13.64%
(c) decrease by 15%
(d) decrease by 18.75%
(e) decrease by 30%
Source: Gmat Cat By Nill (Peterson)
Let, Initially
Length (L) = 6
Breadth (B) = 4
Height (H) = 2
Total Area of Walls = 2(BH + LH) = 2*(4*2 + 6*2) = 2*(8+12) = 40
Then, Finally
Length (L) = 2*6 = 12
Breadth (B) = 4/2 = 2
Height (H) = 2/2 = 1
Total Area of Walls = 2(BH + LH) = 2*(2*1 + 12*1) = 2*(2+12) = 28
% change in Area of four walls = (Final Area - Initial Area)*100 / Initial Area
i.e. % change in Area of four walls = (28 - 40)*100 /40 = - 30% (Decrease)
Answer: Option E
General Discussion
jayanthjanardhan
Joined: 29 May 2013
Last visit: 17 Aug 2017
Posts: 84
Given Kudos: 42
Location: India
Concentration: Technology, Marketing
Schools: Merage '18 (M) Marshall '18 (I) UCSD '18 (II)
WE:Information Technology (Consulting)
21 Jul 2015, 23:34
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GMATinsight
GMATnavigator
The length, breadth and height of a room are in the ratio 3 : 2 : 1. If the breadth and height are halved while the length is doubled, then the total area of the four walls of the room will
(a) remain the same
(b) decrease by 13.64%
(c) decrease by 15%
(d) decrease by 18.75%
(e) decrease by 30%
Source: Gmat Cat By Nill (Peterson)
(a) remain the same
(b) decrease by 13.64%
(c) decrease by 15%
(d) decrease by 18.75%
(e) decrease by 30%
Source: Gmat Cat By Nill (Peterson)
Let, Initially
Length (L) = 6
Breadth (B) = 4
Height (H) = 2
Total Area of Walls = 2(BH + LH) = 2*(4*2 + 6*2) = 2*(8+12) = 40
Then, Finally
Length (L) = 2*6 = 12
Breadth (B) = 4/2 = 2
Height (H) = 2/2 = 1
Total Area of Walls = 2(BH + LH) = 2*(2*1 + 12*1) = 2*(2+12) = 28
% change in Area of four walls = (Final Area - Initial Area)*100 / Initial Area
i.e. % change in Area of four walls = (28 - 40)*100 /40 = - 30% (Decrease)
Answer: Option E
Hi GMATInsight,
Are we not taking the surface area of a rectangular box? in which case, the formula to calculate the surface area is 2(LH+BH+LB)?
