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The line represented by the equation y = 4 – 2x is the perpendicular
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18 Feb 2012, 18:55
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The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P? (A) (–4, 1) (B) (–2, 2) (C) (0, 1) (D) (0, –1) (E) (2, 0) How come the answer will be D? This is how I am trying to solve this.
First, rewrite the line y=42x as y = 2x+4 The equation is now in the form y = mx+b where m represents the slope and b represents the yintercept.Thus, the slope of this line is 2. By definition, if a line is the perpendicular bisector of any line, the slope of line which is perpendicular bisector is the negative inverse of the slope of line G. Since we are told that the line y = 2x+4 is the perpendicular bisector of line segment RP, line segment RP must have a slope of \(\frac{1}{2}\) (which is the negative inverse of slope of line y). Now we know that the slope of the line containing segment RP is\(\frac{1}{2}\) but we do not know its yintercept. We can write the equation of this line as , y = 1/2x+b, where b represents the unknown yintercept. To solve for b, we can use the given information that the coordinates of point R are (4, 1). Since point R is on the line y = 1/2x+b, we can plug 4 in for x and 1 in for y to get b = 1 Therefore, equation of line RP will become y = 1/2x1 Also , y = 2x +4 (Equation of perpendicular bisector) (2)
Equating the two we will get x =2 . Putting this value of x in we get y = 0.
So the points should be (2,0) i.e. answer E.
Where I am getting this wrong guys?
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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18 Feb 2012, 19:12
The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P? A. (–4, 1) B. (–2, 2) C. (0, 1) D. (0, –1) E. (2, 0) Again, there is no need of equations to solve this question. Plot the line y = 4 – 2x (just find the x and y intercepts and draw the line through them): Attachment:
Bisector.png [ 16 KiB  Viewed 37659 times ]
Now, it's easy to SEE that no blue point can be the mirror reflection of R around the line but (0, 1). Answer: D. P.S. Answer cannot possibly be E (2, 0) as this point lies on the line y=42x (substitute the values of x and y to see that it's true).
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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25 Feb 2012, 07:34
Hello,
This is how I solved the problem. Since the Slope of line is 2, the line perpendicular to it would have SLope as 1/2. So I used R(4,1) and each options to see which one gives Slope as 1/2. Only option D gives me the co ordinates through which the SLope is 1/2. It took me around a minutes time to solve.
Please let me know if I'm correct ?




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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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25 Feb 2012, 09:30
priyalr wrote: Hello,
This is how I solved the problem. Since the Slope of line is 2, the line perpendicular to it would have SLope as 1/2. So I used R(4,1) and each options to see which one gives Slope as 1/2. Only option D gives me the co ordinates through which the SLope is 1/2. It took me around a minutes time to solve.
Please let me know if I'm correct ? That's perfectly valid approach. Two lines are perpendicular if and only the product of their slopes is 1. The slope of given line is 2, hence the slope of PR must be 1/2 (negative reciprocal of 2): 1/2*(2)=1. Now, the slope of a line (a line segment) passing through two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(m=\frac{y_2y_1}{x_2x_1}\). So, for our case the slope of PR must be \(m=\frac{1}{2}=\frac{1y_1}{4x_1}\) and you can substitute x and y coordinates of each point from answer choices to see for which one this equation will hold true. Only coordinates of a point from option D fits.
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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01 Jul 2012, 03:10
Bunuel wrote: priyalr wrote: Hello,
This is how I solved the problem. Since the Slope of line is 2, the line perpendicular to it would have SLope as 1/2. So I used R(4,1) and each options to see which one gives Slope as 1/2. Only option D gives me the co ordinates through which the SLope is 1/2. It took me around a minutes time to solve.
Please let me know if I'm correct ? That's perfectly valid approach. Two lines are perpendicular if and only the product of their slopes is 1. The slope of given line is 2, hence the slope of PR must be 1/2 (negative reciprocal of 2): 1/2*(2)=1. Now, the slope of a line (a line segment) passing through two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(m=\frac{y_2y_1}{x_2x_1}\). So, for our case the slope of PR must be \(m=\frac{1}{2}=\frac{1y_1}{4x_1}\) and you can substitute x and y coordinates of each point from answer choices to see for which one this equation will hold true. Only coordinates of a point from option D fits. let's have a look Required slope for line PR = m= 1/2 ( using if two lines are perpendicular then their slopes m1 * m2 = 1 ) option D= ( 0,1) Option E = ( 2, 0) so taking (4,1) and ( 0,1) and finding slope = 2/4 = 1/2 which is of course what we are expecting , now taking (4,1) and (2,0) and finding slope = 1/2 = 1/2 So also E, satisfies the slope method So what am I missing , it is said that only one option satisfies the equation 1/2 = (1y1)/( 4x1) Taking E( 2,0) (10)/(42) = 1/2 and taking D(0,1) (1+1)/(40)= 2/4= 1/2 so both D and E satisfy the slope condition , am I missing anything ?
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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01 Jul 2012, 03:37
stne wrote: Bunuel wrote: priyalr wrote: Hello,
This is how I solved the problem. Since the Slope of line is 2, the line perpendicular to it would have SLope as 1/2. So I used R(4,1) and each options to see which one gives Slope as 1/2. Only option D gives me the co ordinates through which the SLope is 1/2. It took me around a minutes time to solve.
Please let me know if I'm correct ? That's perfectly valid approach. Two lines are perpendicular if and only the product of their slopes is 1. The slope of given line is 2, hence the slope of PR must be 1/2 (negative reciprocal of 2): 1/2*(2)=1. Now, the slope of a line (a line segment) passing through two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(m=\frac{y_2y_1}{x_2x_1}\). So, for our case the slope of PR must be \(m=\frac{1}{2}=\frac{1y_1}{4x_1}\) and you can substitute x and y coordinates of each point from answer choices to see for which one this equation will hold true. Only coordinates of a point from option D fits. let's have a look Required slope for line PR = m= 1/2 ( using if two lines are perpendicular then their slopes m1 * m2 = 1 ) option D= ( 0,1) Option E = ( 2, 0) so taking (4,1) and ( 0,1) and finding slope = 2/4 = 1/2 which is of course what we are expecting , now taking (4,1) and (2,0) and finding slope = 1/2 = 1/2 So also E, satisfies the slope method So what am I missing , it is said that only one option satisfies the equation 1/2 = (1y1)/( 4x1) Taking E( 2,0) (10)/(42) = 1/2 and taking D(0,1) (1+1)/(40)= 2/4= 1/2 so both D and E satisfy the slope condition , am I missing anything ? You can rule out (2,0) (option E), since this point is on the line y=42x.
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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26 Oct 2012, 06:29
Bunuel Bro, my question still remains : I understand E is on the line but why does E also result in slope of 1/2 . . E should cause the slope to be 2 since it is on the line. . why does it then cause the slope to be 1/2? just trying to understand the math of slope here.
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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26 Oct 2012, 06:41
sachindia wrote: Bunuel Bro, my question still remains : I understand E is on the line but why does E also result in slope of 1/2 . . E should cause the slope to be 2 since it is on the line. . why does it then cause the slope to be 1/2?
just trying to understand the math of slope here. Point (2, 0) is on line segment PR (see diagram in my post above). PR is perpendicular to line y = 4 – 2x, thus ANY two point from line segment PR will give you the slope which is negative reciprocal of the slope of line y = 4 – 2x, i.e. 1/2.
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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26 Oct 2012, 09:52
Concrete way is to find the actual coordinates. Slope of RP = 1/2 and by using 4,1 and slope the equation is y=x/2 1 solve for point of intersection  x,y = 2,0. now let P has coordinates (x,y) since intersection is mid point. (x+4)/2 = 2 and (y+1)/2 = 0 thus D
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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02 Nov 2012, 00:45
Quote: solve for point of intersection  x,y = 2,0. How do you get to know the point of intersection is 2,0? I understood your solution till the previous step in which you found the equation of the line.
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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02 Nov 2012, 02:07
Sachin9 wrote: Quote: solve for point of intersection  x,y = 2,0. How do you get to know the point of intersection is 2,0? I understood your solution till the previous step in which you found the equation of the line. xintercept is a value of x for y=0 and similarly yintercept is a value of y for x=0. To find xintercept substitute y=0 and find x. To find yintercept substitute x=0 and find y. For more check Coordinate Geometry chapter of Math Book: mathcoordinategeometry87652.htmlHope it helps.
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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11 Nov 2012, 08:08
Bunuel, do you think these coordinates are not unique. Any combination (x,y) for point P that satisfies the equation 22*y = 4x will make RP perpendicular to the line y = 42x. Am I correct to assert that? Brother Karamazov



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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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12 Nov 2012, 10:02
Ousmane wrote: Bunuel, do you think these coordinates are not unique. Any combination (x,y) for point P that satisfies the equation 22*y = 4x will make RP perpendicular to the line y = 42x. Am I correct to assert that? Brother Karamazov No, that's not correct. Line y = 4 – 2x not only has to be perpendicular of PR but also has to be bisector of PR (line y = 4 2x cuts PR into two equal parts at 90°). Therefore the coordinates of P are unique. Hope it's clear.
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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01 Sep 2017, 11:59
enigma123 wrote: The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P?
(A) (–4, 1) (B) (–2, 2) (C) (0, 1) (D) (0, –1) (E) (2, 0)
If the line y = 4  2x is the perpendicular bisector of line segment RP, then it’s perpendicular to RP at the midpoint of RP. Recall that two lines are perpendicular if their slopes are negative reciprocals of each other. Since the line has a slope of 2, the line segment should have a slope of ½. Thus, let’s first determine which answer choice can be point P so that the slope of RP is ½. We’ll use the slope formula: m = (y2  y1)/(x2  x1): A) (4, 1) m = (1  1)/(4  (4)) = 0 Point P can’t be (4, 1). B) (2, 2) m = (1  2)/(4  (2)) = 1/6 Point P can’t be (2, 2). C) (0, 1) m = (1  1)/(4  0) = 0 Point P can’t be (0, 1). D) (0, 1) m = (1  (1))/(4  0) = 2/4 = 1/2 Point P could be (0, 1). E) (2, 0) m = (1  0)/(4  2) = 1/2 Point P could be (2, 0). We see that point P could be either (0, 1) or (2, 0), since either one will make RP’s slope ½. Next let’s determine the midpoint of RP if P is either (0, 1) or (2, 0). We use the midpoint formula: ((x1 + x2)/2 , (y1 + y2)/2)). Recall that R = (4,1). If P = (0, 1), then the midpoint of RP = ((4 + 0)/2, (1 + (1))/2) = (2, 0). If P = (2, 0), then the midpoint of RP = ((4 + 2)/2, (1 + 0)/2) = (3, 1/2). Recall that the line y = 4  2x has to include the midpoint of RP. In other words, the midpoint of RP is a point on the line, and hence its coordinates will satisfy the equation of the line. If P = (0, 1) and the midpoint of RP is (2, 0), is 0 = 4  2(2)? The answer is yes, since 0 = 0. We can see that choice D is the correct choice. However, let’s also show that choice E is not the correct choice: If P = (2, 0) and the midpoint of RP is (3, 1/2), is 1/2 = 4  2(3)? The answer is no, since 1/2 ≠ 2. Alternate Solution: Since the line segment RP is perpendicular to y = 4  2x, the line containing RP must have a slope of 1/2, since the slopes of perpendicular lines are negative reciprocals of each other. Then, the line containing the line segment RP must be of the form y = (1/2)x + b, for some real number b. Since this line contains the point R, its equation must be satisfied when we substitute x = 4 and y = 1; therefore 1 = (1/2)(4) + b. Then, 1 = 2 + b, and thus b = 1. We know the line that contains the line segment RP has an equation y = (1/2)x  1. Let’s find the common point of this line with y = 4  2x. We set (1/2)x  1 = 4  2x and solve for x: (1/2)x 1 = 4  2x (5/2)x = 5 x = 2 So, the xcoordinate of the common point is 2. We can substitute x = 2 in either equation to find the ycoordinate: y = 4  2(2) = 0. So, the common point is (2, 0). Note that this common point is the midpoint of R and P. Therefore, if we let P = (a, b), we must have: (a + 4)/2 = 2 and (b + 1)/2 = 0. We find that a = 0 and b = 1. Thus, P = (0, 1). Answer: D
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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06 Oct 2019, 10:08
enigma123 wrote: The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P? (A) (–4, 1) (B) (–2, 2) (C) (0, 1) (D) (0, –1) (E) (2, 0) How come the answer will be D? This is how I am trying to solve this.
First, rewrite the line y=42x as y = 2x+4 The equation is now in the form y = mx+b where m represents the slope and b represents the yintercept.Thus, the slope of this line is 2. By definition, if a line is the perpendicular bisector of any line, the slope of line which is perpendicular bisector is the negative inverse of the slope of line G. Since we are told that the line y = 2x+4 is the perpendicular bisector of line segment RP, line segment RP must have a slope of \(\frac{1}{2}\) (which is the negative inverse of slope of line y). Now we know that the slope of the line containing segment RP is\(\frac{1}{2}\) but we do not know its yintercept. We can write the equation of this line as , y = 1/2x+b, where b represents the unknown yintercept. To solve for b, we can use the given information that the coordinates of point R are (4, 1). Since point R is on the line y = 1/2x+b, we can plug 4 in for x and 1 in for y to get b = 1 Therefore, equation of line RP will become y = 1/2x1 Also , y = 2x +4 (Equation of perpendicular bisector) (2)
Equating the two we will get x =2 . Putting this value of x in we get y = 0.
So the points should be (2,0) i.e. answer E.
Where I am getting this wrong guys? Similar question to practice: http://gmatclub.com/forum/intherectan ... 44774.htmlhttp://gmatclub.com/forum/inthexycoo ... 43502.htmlhttp://gmatclub.com/forum/intherectan ... 32646.htmlhttp://gmatclub.com/forum/intherectan ... 88473.htmlhttp://gmatclub.com/forum/intherectan ... 29932.html
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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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06 Oct 2019, 11:15
enigma123 wrote: The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P? (A) (–4, 1) (B) (–2, 2) (C) (0, 1) (D) (0, –1) (E) (2, 0) How come the answer will be D? This is how I am trying to solve this.
First, rewrite the line y=42x as y = 2x+4 The equation is now in the form y = mx+b where m represents the slope and b represents the yintercept.Thus, the slope of this line is 2. By definition, if a line is the perpendicular bisector of any line, the slope of line which is perpendicular bisector is the negative inverse of the slope of line G. Since we are told that the line y = 2x+4 is the perpendicular bisector of line segment RP, line segment RP must have a slope of \(\frac{1}{2}\) (which is the negative inverse of slope of line y). Now we know that the slope of the line containing segment RP is\(\frac{1}{2}\) but we do not know its yintercept. We can write the equation of this line as , y = 1/2x+b, where b represents the unknown yintercept. To solve for b, we can use the given information that the coordinates of point R are (4, 1). Since point R is on the line y = 1/2x+b, we can plug 4 in for x and 1 in for y to get b = 1 Therefore, equation of line RP will become y = 1/2x1 Also , y = 2x +4 (Equation of perpendicular bisector) (2)
Equating the two we will get x =2 . Putting this value of x in we get y = 0.
So the points should be (2,0) i.e. answer E.
Where I am getting this wrong guys? Equation of Perpendicular Bisector is Y=42X Equation of a line perpendicular to this line Y=1/2X+C This line passes through (4,1) 1=1/2 *4 +C C=1 Equation of line through which perpendicular bisector passes or equation of line RP is Y=1/2 X1 Coordinates of point P must pass through this Equation At X=0, Y=1 So (0,1) But (2,0) also satisfies this condition. If (2,0) is the coordinates of point P Then Mid point of RP(3,1/2), and this must be pass through the line of perpendicular bisector i.e Y=42X at X =3, Y=2( Not 1/2) So (2,0) is not the coordinates of point P D:)



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Re: The line represented by the equation y = 4 – 2x is the perpendicular
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09 Oct 2019, 03:18
for eqn y = 4 – 2x slope= 2 so for line with coordiante (4,1) the slope should be 1/2 since both are perpendicular so m1*m2=1 we get 1/2 for (4,1) & ( 0,1) only IMO D enigma123 wrote: The line represented by the equation y = 4 – 2x is the perpendicular bisector of line segment RP. If R has the coordinates (4, 1), what are the coordinates of point P? (A) (–4, 1) (B) (–2, 2) (C) (0, 1) (D) (0, –1) (E) (2, 0) How come the answer will be D? This is how I am trying to solve this.
First, rewrite the line y=42x as y = 2x+4 The equation is now in the form y = mx+b where m represents the slope and b represents the yintercept.Thus, the slope of this line is 2. By definition, if a line is the perpendicular bisector of any line, the slope of line which is perpendicular bisector is the negative inverse of the slope of line G. Since we are told that the line y = 2x+4 is the perpendicular bisector of line segment RP, line segment RP must have a slope of \(\frac{1}{2}\) (which is the negative inverse of slope of line y). Now we know that the slope of the line containing segment RP is\(\frac{1}{2}\) but we do not know its yintercept. We can write the equation of this line as , y = 1/2x+b, where b represents the unknown yintercept. To solve for b, we can use the given information that the coordinates of point R are (4, 1). Since point R is on the line y = 1/2x+b, we can plug 4 in for x and 1 in for y to get b = 1 Therefore, equation of line RP will become y = 1/2x1 Also , y = 2x +4 (Equation of perpendicular bisector) (2)
Equating the two we will get x =2 . Putting this value of x in we get y = 0.
So the points should be (2,0) i.e. answer E.
Where I am getting this wrong guys?




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