Attachment:
11.png [ 11.99 KiB | Viewed 7727 times ]
OFFICIAL EXPLANATIONAs determined in the analysis of the question, the lines are two pairs of parallel lines, so their intersection forms a parallelogram. Determine the coordinates of the points by setting x to 3 and then to 9 in the third and fourth equations.
\(y=−\frac{1}{3}*(3)+4=3\)
\(y=−\frac{1}{3}*(3)+10=9\)
So the coordinates of the intersection of x = 3 with the other two lines are (3, 3) and (3, 9).
\(y=−\frac{1}{3}*(9)+4=1\)
\(y=−\frac{1}{3}*(9)+10=7\\
\)
The coordinates of the intersections with x = 9 are (9, 1) and (9, 7).
The area of a parallelogram is base × height. If you consider a side parallel to the y-axis the base, then the height is the distance between the two parallel lines, as shown by the dotted line on the sketch. So, the base is 7 − 1 = 6, and the height is 9 − 3 = 6. Therefore, the area of the parallelogram is 6 × 6 = 36, which is (C).