Smita04
The mode of a set of integers is x. what is the difference between the median of this set of integers and x?
(1) The difference between any two integers in the set is less than 3.
(2) The average of the set of integers s x.
Mode is the most frequent number. It could appear in the beginning, middle or end so has no connection to median, the middle number. We need to find a unique value for Median - x.
(1) The difference between any two integers in the set is less than 3.
So the integers would have a difference of 0/1/2.
They could be {1, 1, 2, 3} - median = 1.5 and x = 1
or {1, 2, 2, 3} - median = 2 and x = 2
etc
No unique value for median - x.
(2) The average of the set of integers is x.
Mode = x = Average
Since average is often somewhere in the middle, we could take some simple examples such as
Numbers could be {1, 2, 3, 3, 6} - median = 3 and x = 3
or {1, 2, 3, 4, 4, 10} - median = 3.5 and x = 4
Using both, we know that all we can have are at max three consecutive integers.
x is in the middle since it is the average. It also appears maximum number of times. So if x = 5, other integers can only be 4 and/or 6. Since 5 is the average too, if there is a 4, there must be a 6 too. For every 4, there should be a 6 to make up the deficit. So something like this is possible
{4, 4, 5, 5, 5, 6, 6}
or
{4, 5, 5,5 ,5 ,5 ,5 6}
or
{4, 4, 4,4, 5, 5, 5, 5, 5, 6, 6, 6, 6}
Since x is the mode too, it will outnumber 4s and 6s. So the middle value will always be x only. Difference between median and x will be 0.
Answer (C)