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SD is dependent on the spread of numbers from MEDIAN.

I think it must be mean, spread from mean. Here given sequence is in AP, so MEAN= MEDIAN.
Am I correct?

chetan2u
he \(n_{th}\) term, where n > 1, in a sequence S of positive integers is defined by \(t_n=t_{n-­1}+4\). What is the standard deviation of the elements in S?
So it is an AP with a difference of 4 between consecutive terms..
SD is dependent on the spread of numbers from MEDIAN. Here we know the spread of consecutive terms, so if we know the total numbers in the set, we would know the SD

(1) The sequence contains 11 elements.
EXACTLY what we were looking for. Irrespective of where the numbers lie, the SD will be same..
The spread will be Median-the extreme numbers, which is 4*4, and so on till the immediate numbers, which is 4, so 2((4*4)+(4*3)+(4*2)+(4*1)). This will be constant irrespective of set starting with 10, 100, 10000 etc
Suff

(2) The first element in the sequence is 7.
Insuff

A
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gvij2017
SD is dependent on the spread of numbers from MEDIAN.

I think it must be mean, spread from mean. Here given sequence is in AP, so MEAN= MEDIAN.
Am I correct?

chetan2u
he \(n_{th}\) term, where n > 1, in a sequence S of positive integers is defined by \(t_n=t_{n-­1}+4\). What is the standard deviation of the elements in S?
So it is an AP with a difference of 4 between consecutive terms..
SD is dependent on the spread of numbers from MEDIAN. Here we know the spread of consecutive terms, so if we know the total numbers in the set, we would know the SD

(1) The sequence contains 11 elements.
EXACTLY what we were looking for. Irrespective of where the numbers lie, the SD will be same..
The spread will be Median-the extreme numbers, which is 4*4, and so on till the immediate numbers, which is 4, so 2((4*4)+(4*3)+(4*2)+(4*1)). This will be constant irrespective of set starting with 10, 100, 10000 etc
Suff

(2) The first element in the sequence is 7.
Insuff

A

Yes, you are correct.
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Bunuel
The \(n_{th}\) term, where n > 1, in a sequence S of positive integers is defined by \(t_n=t_{n-­1}+4\). What is the standard deviation of the elements in S?

(1) The sequence contains 11 elements.
(2) The first element in the sequence is 7.


\(sd=\sqrt{\frac{((a_1-mean)^2+(a_2-mean)^2…)}{n}}\)

set: {1,2,3} n: 3 mean: 2
term-mean: {-1,0,1}
sum squared: {1+0+1}=2
sd=√2/3

set: {2,3,4} n: 3 mean: 3
term-mean: {-1,0,1}
sum squared: {1+0+1}=2
sd=√2/3

set: {1,2,3,4,5} n: 5 mean: 3
term-mean: {-2,-1,0,1,2}
sum squared: {4+1+0+1+4}=10
sd=√10/5=√2

Conclusion: number of terms in an AP affects the sd, but the value of the first element does not.

Ans (A)
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chetan2u
The \(n_{th}\) term, where n > 1, in a sequence S of positive integers is defined by \(t_n=t_{n-­1}+4\). What is the standard deviation of the elements in S?
So it is an AP with a difference of 4 between consecutive terms..
SD is dependent on the spread of numbers from MEDIAN or MEAN in an AP as Median=Mean in an AP. Here we know the spread of consecutive terms, so if we know the total numbers in the set, we would know the SD

(1) The sequence contains 11 elements.
EXACTLY what we were looking for. Irrespective of where the numbers lie, the SD will be same..
The spread will be Median-the extreme numbers, which is 4*4, and so on till the immediate numbers, which is 4, so 2((4*4)+(4*3)+(4*2)+(4*1)). This will be constant irrespective of set starting with 10, 100, 10000 etc
Suff

(2) The first element in the sequence is 7.
Insuff

A
­Hi chetan2u
I chose D, and I fail to understand how the 2nd statement will not help in arriving at the SD.
If we know t1, which is, 7, then we can find out the entire AP,
7, 7+4, 7+8, 7+12 .... => 7, 11, 15, 19, ...., 47
and then we can calculate the SD.

Is there something I am missing?

Thank you in advance.
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zlishz

chetan2u
The \(n_{th}\) term, where n > 1, in a sequence S of positive integers is defined by \(t_n=t_{n-­1}+4\). What is the standard deviation of the elements in S?
So it is an AP with a difference of 4 between consecutive terms..
SD is dependent on the spread of numbers from MEDIAN or MEAN in an AP as Median=Mean in an AP. Here we know the spread of consecutive terms, so if we know the total numbers in the set, we would know the SD

(1) The sequence contains 11 elements.
EXACTLY what we were looking for. Irrespective of where the numbers lie, the SD will be same..
The spread will be Median-the extreme numbers, which is 4*4, and so on till the immediate numbers, which is 4, so 2((4*4)+(4*3)+(4*2)+(4*1)). This will be constant irrespective of set starting with 10, 100, 10000 etc
Suff

(2) The first element in the sequence is 7.
Insuff

A
­Hi chetan2u
I chose D, and I fail to understand how the 2nd statement will not help in arriving at the SD.
If we know t1, which is, 7, then we can find out the entire AP,
7, 7+4, 7+8, 7+12 .... => 7, 11, 15, 19, ...., 47
and then we can calculate the SD.

Is there something I am missing?

Thank you in advance.
­You do not how many elements are there in the sequence
If there are only 2 elements, the answer will be different from when there are are 100 elements.

I believe you are carrying the information from statement 1 to statement 2 when read alone.
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