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The number n of units of its product that Company X is scheduled to produce in month t of its next fiscal year is given by the formula \(n = \frac{900}{1+c2^{-t}}\), where c is a constant and t is a positive integer between 1 and 6, inclusive. What is the number of units of its product that Company X is scheduled to produce in month 6 of its next fiscal year?
(1) Company X is scheduled to produce 180 units of its product in month 1 of its next fiscal year.
(2) Company X is scheduled to produce 300 units of its product in month 2 of its next fiscal year.
(1) Company X is scheduled to produce 180 units of its product in month 1 of its next fiscal year.
(2) Company X is scheduled to produce 300 units of its product in month 2 of its next fiscal year.
23 Jul 2018, 18:53
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The number n of units of its product that Company X is scheduled to produce in month t of its next fiscal year is given by the formula \(n = \frac{900}{1+c2^{-t}}\), where c is a constant and t is a positive integer between 1 and 6, inclusive. What is the number of units of its product that Company X is scheduled to produce in month 6 of its next fiscal year?
\(n = \frac{900}{1+c2^{-t}}\)
There are two variables ,c, which is constant and t depends on the month we are talking about. Here t is given as 6 we require value of c..
(1) Company X is scheduled to produce 180 units of its product in month 1 of its next fiscal year.
n and t are given, so we can easily find c, so sufficient
\(n = \frac{900}{1+c2^{-t}}\)......\(180= \frac{900}{1+c2^{-1}}..........180=\frac{900}{(1+c/2)}.\),
\(1+c/2=5......c=8\)
Sufficient
(2) Company X is scheduled to produce 300 units of its product in month 2 of its next fiscal year.
n and t are given, so we can easily find c, so sufficient
\(n = \frac{900}{1+c2^{-t}}\)......\(300= \frac{900}{1+c2^{-2}}..........300=\frac{900}{(1+c/4)}.\),
\(1+c/4=3......c=8\)
Sufficient
D
\(n = \frac{900}{1+c2^{-t}}\)
There are two variables ,c, which is constant and t depends on the month we are talking about. Here t is given as 6 we require value of c..
(1) Company X is scheduled to produce 180 units of its product in month 1 of its next fiscal year.
n and t are given, so we can easily find c, so sufficient
\(n = \frac{900}{1+c2^{-t}}\)......\(180= \frac{900}{1+c2^{-1}}..........180=\frac{900}{(1+c/2)}.\),
\(1+c/2=5......c=8\)
Sufficient
(2) Company X is scheduled to produce 300 units of its product in month 2 of its next fiscal year.
n and t are given, so we can easily find c, so sufficient
\(n = \frac{900}{1+c2^{-t}}\)......\(300= \frac{900}{1+c2^{-2}}..........300=\frac{900}{(1+c/4)}.\),
\(1+c/4=3......c=8\)
Sufficient
D
General Discussion
23 Nov 2011, 12:51
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Rephrasing the question gives us "What is the value of c?"
St1: This gives a linear equation with only one variable c. We can find c. Sufficient.
St2: This also gives a linear equation with only one variable c. We can find c.
Sufficient.
Ans: D
St1: This gives a linear equation with only one variable c. We can find c. Sufficient.
St2: This also gives a linear equation with only one variable c. We can find c.
Sufficient.
Ans: D
