Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1810:00 AM PDT
-11:00 AM PDT
Join us in a live GMAT practice session and solve 25 challenging GMAT questions with other test takers in timed conditions, covering GMAT Quant, Data Sufficiency, Data Insights, Reading Comprehension, and Critical Reasoning questions.
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products. Ends 6/1
May 1501:00 PM IST
-11:00 AM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 735+ score.- May 19
12:00 PM PDT
-01:00 PM PDT
Scoring 329 on the GRE is not always about using more books, more courses, or a longer study plan. In this episode of GRE Success Talks, Ashutosh shares his GRE preparation strategy, study plan, and test-day experience, explaining how he kept his prep.... - Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
02 Mar 2020, 03:37
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
42% (02:50) correct
58%
(02:53)
wrong
based on 127
sessions
History
Date
Time
Result
Not Attempted Yet
The number of ordered pairs of integers (x, y) satisfying the equation \(x^2 + 4y^2 < 100\) is:
A. 90
B. 95
C. 147
D. 180
E. 185
Are You Up For the Challenge: 700 Level Questions
A. 90
B. 95
C. 147
D. 180
E. 185
Are You Up For the Challenge: 700 Level Questions
02 Mar 2020, 03:53
Kudos
Bookmarks
y=0, x^2<100 or x can be from -9 to 9 (19 values)
y=1 or -1, x^2 <96 or x can be from -9 to 9 (19 values)
y=2 or -2, x^2<84 or x can be from -9 to 9 (19 values)
y=3 or -3, x^2<64 or x can be from -7 to 7 (15 values)
y=4 or -4, x^2<36 or x can be from -5 to 5 (11 values)
y=5 or -5, x^2<0 or x cab take 0 value
Total number of solutions= 19+(2*19)+(2*19)+(2*15)+(2*11)=147
y=1 or -1, x^2 <96 or x can be from -9 to 9 (19 values)
y=2 or -2, x^2<84 or x can be from -9 to 9 (19 values)
y=3 or -3, x^2<64 or x can be from -7 to 7 (15 values)
y=4 or -4, x^2<36 or x can be from -5 to 5 (11 values)
y=5 or -5, x^2<0 or x cab take 0 value
Total number of solutions= 19+(2*19)+(2*19)+(2*15)+(2*11)=147
Bunuel
General Discussion
02 Mar 2020, 03:59
Kudos
Bookmarks
Bunuel
\(x^2 + 4y^2 < 100\)
SInce we have to take squares of values of x and y therefore the signs of x and y do not matter so
The solutions of \(x^2 + 4y^2 < 100\) at x= +1
\(1 + 4y^2 < 100\)
\(4y^2 < 99\)
\(y^2 < 24.75\)
\( -5 < y < 5\)
i.e. Available Values of x = 2 and for those values of x, values of y = 9 [Integers including -4 to +4]
i.e. Total Solutions = 2*9 = 18
The solutions of \(x^2 + 4y^2 < 100\) at x= +2
\(4 + 4y^2 < 100\)
\(4y^2 < 96\)
\(y^2 < 24\)
\( -5 < y < 5\)
i.e. Available Values of x = 2 and for those values of x, values of y = 9 [Integers including -4 to +4]
i.e. Total Solutions = 2*9 = 18
Similarly, at x= +3, \(-4.77 < y < 4.77\)
i.e. Available Values of x = 2 and for those values of x, values of y = 9 [Integers including -4 to +4]
i.e. Total Solutions = 2*9 = 18
Similarly, at x= +4, \(-4.58 < y < 4.58\)
i.e. Available Values of x = 2 and for those values of x, values of y = 9 [Integers including -4 to +4]
i.e. Total Solutions = 2*9 = 18
Similarly, at x= +5, \(-4.33 < y < 4.33\)
i.e. Available Values of x = 2 and for those values of x, values of y = 9 [Integers including -4 to +4]
i.e. Total Solutions = 2*9 = 18
Similarly, at x= +6, \(-4 < y < 4\)
i.e. Available Values of x = 2 and for those values of x, values of y = 7 [Integers including -3 to +3]
i.e. Total Solutions = 2*7 = 14
Similarly, at x= +7, \(-3.5 < y < 3.5\)
i.e. Available Values of x = 2 and for those values of x, values of y = 7 [Integers including -3 to +3]
i.e. Total Solutions = 2*7 = 14
Similarly, at x= +8, \(-3 < y < 3\)
i.e. Available Values of x = 2 and for those values of x, values of y = 5 [Integers including -2 to +2]
i.e. Total Solutions = 2*5 = 10
Similarly, at x= +9, \(-2.17 < y < 2.17\)
i.e. Available Values of x = 2 and for those values of x, values of y = 5 [Integers including -2 to +2]
i.e. Total Solutions = 2*5 = 10
Similarly, at x= 0, \(-5 < y < 5\)
i.e. Available Values of x = 1 and for those values of x, values of y = 9 [Integers including -4 to +4]
i.e. Total Solutions = 1*9 = 9
at x= +10, NO SOLUTION
Total Solutions = 18*5+14*2+10*2+9 = 90+28+20+9 = 147
Answer: Option C
