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The number of ways to distribute 8 different books to David, Liam and Sophia so that David is given 2 of the books, Liam is given 3 and Sophia is given 3 is equal to:
A. 8!/(2!*3!*3!)
B. 8!/(2!*3!)
C. 8!/(3!)
D. 8!/(2!)
E. 8!
8!/(2!)(3!)(3!)=560
Bunuel karishma can you please help me understand this? Can you also share links to similar qs? Thank you!
Source- Advance Q- Qs 3- Tips section
Consider those 8 different books in a row:
1 - 2 - 3 - 4 - 5 - 6 - 7 - 8
Next, imagine 2 D's, 3 L's and 3 S's. We can arrange these 8 letters in 8!/(2!*3!*3!), each arrangement giving different distribution of books among David, Liam and Sophia. For example,
1 - 2 - 3 - 4 - 5 - 6 - 7 - 8
S - D - D - L - L - S - S - L
This would mean that Sophia gets books 1, 6, and 7; David gets books 2 and 3; and Liam gets books 4, 5, and 8.
Answer: A.
For similar questions check
DISTRIBUTING ITEMS/PEOPLE/NUMBERS... (QUESTION COLLECTION)Hope it helps.