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The perimeter of a rectangle is 6w. If one side w as length w/2 what

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Joined: 02 Sep 2009
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The perimeter of a rectangle is 6w. If one side w as length w/2 what  [#permalink]

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New post 11 Jan 2019, 00:41
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

77% (01:20) correct 23% (01:57) wrong based on 13 sessions

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Re: The perimeter of a rectangle is 6w. If one side w as length w/2 what  [#permalink]

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New post 11 Jan 2019, 00:47
OA is B

2(l+b)=6w
so l+b=3w
if one of the sides is 1/2w then the longer side is 2.5w, when multiplied gives 2.5w^2/2, the only answer that matches the fractional value is B.

Bunuel wrote:
The perimeter of a rectangle is 6w. If one side w as length w/2 what is the area of the rectangle?

A. w^2/4

B. 5w^2/4

C. 5w^2/2

D. 11w^2/4

E. 11w^2/2

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Re: The perimeter of a rectangle is 6w. If one side w as length w/2 what  [#permalink]

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New post 11 Jan 2019, 02:50
Bunuel wrote:
The perimeter of a rectangle is 6w. If one side w as length w/2 what is the area of the rectangle?

A. w^2/4

B. 5w^2/4

C. 5w^2/2

D. 11w^2/4

E. 11w^2/2



2 * (l+b) = w
b = 5w/2 ; l= w/2

area ; 5 w^2/4
IMO B
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Re: The perimeter of a rectangle is 6w. If one side w as length w/2 what  [#permalink]

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New post 11 Jan 2019, 03:11
Bunuel wrote:
The perimeter of a rectangle is 6w. If one side w as length w/2 what is the area of the rectangle?

A. w^2/4

B. 5w^2/4

C. 5w^2/2

D. 11w^2/4

E. 11w^2/2


IMO Answer B

2(l+b) = 6w
l+b = 3w

l=w/2

b will be now 5w/ 2

Area of a rectangle = l * b
=>\(\frac{5w^2}{4}\)
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Re: The perimeter of a rectangle is 6w. If one side w as length w/2 what &nbs [#permalink] 11 Jan 2019, 03:11
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