The population of a village is calculated by adding the number of male

The population of a village is calculated by adding the number of males and the number of females.If this year male population increased by 10% as compared to last year, what is the net percentage change in total population of the village?

(1) The number of females as compared with last year increased this year by 5%.
(2) The ratio of the number of females and the males was 2:3 last year.

Last year: males = 100x, females = 100y
this year: males = 110x, females = ?

net percentage change = \(\frac{(T(P) - L(P))*100}{L(P)}\)
where T(P): total population this year & L(P) : total population last year

statement 1:
this year: males = 110x females = 105y
net percentage change = \(\frac{(110x + 105y - (100x + 100y))*100}{100(x+y)}\) = \(\frac{10x + 5y }{(x+y)}\)
we do not know value of x & y.
not sufficient

statement 2:
ratio of \(\frac{100y}{100x}\) = \(\frac{2}{3}\)
not sufficient

combining both statements,
y = \(\frac{2x}{3}\)
net percentage change =\(5(2x + {\frac{2x}{3}})\)/\((x+\frac{2x}{3})\)
x will get cancelled out leaving us with a unique value
sufficient
Ans: C