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The probability of getting a '6' on a role of die is 1/6. If this die

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New post 24 Nov 2019, 10:45
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The probability of getting a '6' on a role of die is 1/6. If this die is rolled
4 times, what is the probability of getting a '6' at least 2 times?

(A) \((1/6)^4\)
(B) \(2(1 /6)^3(5/6) + (1/6)^4\)
(C) \(6(1/6)^2(5/6)^2 + 4(1/6)^3(5/6) + (1/6)^4\)
(D) \(12(1/6)^2(5/6)^2 + 4(1/6)^3(5/6) + (1/6)^4\)
(E) \(12(1/6)^2(5/6)^2 + 6(1/6)^3(5/6) + (1/6)^4\)
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New post 01 Dec 2019, 02:05
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Re: The probability of getting a '6' on a role of die is 1/6. If this die  [#permalink]

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New post 01 Dec 2019, 02:30
fauji wrote:
The probability of getting a '6' on a role of die is 1/6. If this die is rolled
4 times, what is the probability of getting a '6' at least 2 times?

(A) \((1/6)^4\)
(B) \(2(1 /6)^3(5/6) + (1/6)^4\)
(C) \(6(1/6)^2(5/6)^2 + 4(1/6)^3(5/6) + (1/6)^4\)
(D) \(12(1/6)^2(5/6)^2 + 4(1/6)^3(5/6) + (1/6)^4\)
(E) \(12(1/6)^2(5/6)^2 + 6(1/6)^3(5/6) + (1/6)^4\)


total ways ; 4c2 * ( 5/6)^2*(1/6)^2 + 4c1* (1/6)^3*(5/6) + (1/6)6
IMO C \(6(1/6)^2(5/6)^2 + 4(1/6)^3(5/6) + (1/6)^4\)
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Re: The probability of getting a '6' on a role of die is 1/6. If this die   [#permalink] 01 Dec 2019, 02:30
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