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salt : sugar : water
3:5:7
sugar : salt : water will be;
5:3:7


sugar : salt is double while sugar : water remains the same
10 : 3 :14
5: 1.5 :7

so A
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Initial

Sugar:Salt:Water = 5:3:7

Final

Sugar:Salt:Water = 10:3:14

14x=7

x=0.5

Therefore, final concentration of salt = 3*0.5 = 1.5

Answer is (A)

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Bunuel
The ratio, by volume, of salt to sugar to water in a certain solution is 3:5:7. The solution will be altered so the ratio of sugar to salt is doubled while the ratio of sugar to water is maintained. If altered solution will contain 7 cubic centimeters of water, how many cubic centimeters of salt will it contain?

A. 1.5
B. 3
C. 5
D. 10
E. 14

The original ratio is:

Salt : sugar : water = 3 : 5 : 7

Since sugar to salt is doubled, we have:

sugar/salt = 10/3

Since the ratio of sugar to water is maintained, we have:

sugar/water = 10/14

The new ratio is:

Salt : sugar : water = 3x : 10x : 14x

Since there are 7 cubic centimeters of water:

14x = 7

x = 1/2

Thus, salt is 3 x 1/2 = 1.5 cubic centimeters.

Answer: A
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Deconstructing the Question

Initial ratio (salt : sugar : water) = 3 : 5 : 7.
The solution is altered so that the ratio sugar : salt is doubled, while sugar : water is maintained.
In the altered solution, water = 7 cm^3. Find the salt amount.

Step-by-step

Maintain sugar:water:
\(\text{sugar}:\text{water} = 5:7\)
If water = \(7\), then sugar = \(5\).

Originally:
\(\frac{\text{sugar}}{\text{salt}} = \frac{5}{3}\)

Doubled:
\(\frac{\text{sugar}}{\text{salt}} = 2\cdot\frac{5}{3} = \frac{10}{3}\)
So:
\(\text{sugar}:\text{salt} = 10:3\)

If sugar = \(5\), then 10 parts = 5, so 1 part = 0.5.
Salt = 3 parts:
\(3 \cdot 0.5 = 1.5\)

Answer: A (1.5)
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