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# The remainder of the division of a number by 63 is 27. What

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Current Student
Joined: 22 Jul 2014
Posts: 123
Concentration: General Management, Finance
GMAT 1: 670 Q48 V34
WE: Engineering (Energy and Utilities)
The remainder of the division of a number by 63 is 27. What  [#permalink]

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05 Aug 2014, 08:24
5
00:00

Difficulty:

5% (low)

Question Stats:

92% (01:07) correct 8% (01:54) wrong based on 190 sessions

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The remainder of the division of a number by 63 is 27. What will be the remainder when that number is divided by 7?

A) 4
B) 5
C) 6
D) 7
E) 8

Source: 4gmat
Manager
Joined: 21 Jul 2014
Posts: 124
Re: The remainder of the division of a number by 63 is 27. What  [#permalink]

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05 Aug 2014, 08:30
alphonsa wrote:
The remainder of the division of a number by 63 is 27. What will be the remainder when that number is divided by 7?

A) 4
B) 5
C) 6
D) 7
E) 8

Source: 4gmat

The easiest way to solve this question is by plugging in a number. Here are the steps I followed:

1) Choose a number X that when divided by 63 gives you 27 as a remainder. So I did x = 63 + 27 = 90. (90/63 = 1R27)
2) Divide that number by 7. 90/7 = 12R6

Since the remainder is 6, the correct answer is choice C.

These types of problems typically come in a data sufficiency type question, in which case you would have tried to validate the pattern by trying one or two more numbers. But since the question here is very straight forward, you don't need to do any more work.
Current Student
Joined: 22 Jul 2014
Posts: 123
Concentration: General Management, Finance
GMAT 1: 670 Q48 V34
WE: Engineering (Energy and Utilities)
Re: The remainder of the division of a number by 63 is 27. What  [#permalink]

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05 Aug 2014, 08:34
LighthousePrep wrote:
alphonsa wrote:
The remainder of the division of a number by 63 is 27. What will be the remainder when that number is divided by 7?

A) 4
B) 5
C) 6
D) 7
E) 8

Source: 4gmat

The easiest way to solve this question is by plugging in a number. Here are the steps I followed:

1) Choose a number X that when divided by 63 gives you 27 as a remainder. So I did x = 63 + 27 = 90. (90/63 = 1R27)
2) Divide that number by 7. 90/7 = 12R6

Since the remainder is 6, the correct answer is choice C.

These types of problems typically come in a data sufficiency type question, in which case you would have tried to validate the pattern by trying one or two more numbers. But since the question here is very straight forward, you don't need to do any more work.

Actually this problem didnt come with any options.It was given for conceptual understanding.

Considering that no options are given, how would you solve this question?
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Posts: 1823
Location: India
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The remainder of the division of a number by 63 is 27. What  [#permalink]

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05 Aug 2014, 18:00
2
1
alphonsa wrote:
LighthousePrep wrote:
alphonsa wrote:
The remainder of the division of a number by 63 is 27. What will be the remainder when that number is divided by 7?

A) 4
B) 5
C) 6
D) 7
E) 8

Source: 4gmat

The easiest way to solve this question is by plugging in a number. Here are the steps I followed:

1) Choose a number X that when divided by 63 gives you 27 as a remainder. So I did x = 63 + 27 = 90. (90/63 = 1R27)
2) Divide that number by 7. 90/7 = 12R6

Since the remainder is 6, the correct answer is choice C.

These types of problems typically come in a data sufficiency type question, in which case you would have tried to validate the pattern by trying one or two more numbers. But since the question here is very straight forward, you don't need to do any more work.

Actually this problem didnt come with any options.It was given for conceptual understanding.

Considering that no options are given, how would you solve this question?

7 is a multiple of 63;

so if dividing by 63 gives a remainder 27, then continue dividing 27 by 7

27 divided by 7 gives remainder 6

This does not seem to be Difficulty: 600-700 Level question
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Joined: 02 Sep 2009
Posts: 52108
Re: The remainder of the division of a number by 63 is 27. What  [#permalink]

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13 Aug 2014, 07:02
2
2
alphonsa wrote:
The remainder of the division of a number by 63 is 27. What will be the remainder when that number is divided by 7?

A) 4
B) 5
C) 6
D) 7
E) 8

Source: 4gmat

The remainder of the division of a number by 63 is 27: $$x=63q+27=63q+21+6=7(9q+3)+6$$. The first term 7(9q+3) is divisible by 7, hence the remainder will be only from the second term. 6 divided by 7 yields the remainder of 6.

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Location: India
Concentration: Finance, Strategy
GMAT 1: 530 Q39 V23
GMAT 2: 560 Q42 V26
GPA: 3.5
WE: Consulting (Computer Hardware)
Re: The remainder of the division of a number by 63 is 27. What  [#permalink]

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17 Sep 2014, 09:45
alphonsa wrote:
The remainder of the division of a number by 63 is 27. What will be the remainder when that number is divided by 7?

A) 4
B) 5
C) 6
D) 7
E) 8

Source: 4gmat

sol:

let the required number be x

x=63a+27

rem (x/7)= rem (63a+27)/7
= rem (63a/7) + rem (27/7)
= 0 + 6
=6
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Re: The remainder of the division of a number by 63 is 27. What  [#permalink]

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24 Mar 2017, 18:32
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Re: The remainder of the division of a number by 63 is 27. What &nbs [#permalink] 24 Mar 2017, 18:32
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