The table above shows the number of employees at each of four salary : Problem Solving (PS)

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The table above shows the number of employees at each of four salary

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Manager

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The table above shows the number of employees at each of four salary [#permalink]

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Updated on: 22 Apr 2018, 02:38

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Difficulty:

5% (low)

Question Stats:

91% (01:34) correct

9% (01:29) wrong

based on 99 sessions

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The table above shows the number of employees at each of four salary levels at Company X. What is the average (arithmetic mean) salary for the 20 employees?

A. $23,500
B. $23,750
C. $23,900
D. $24,125
E. $24,250

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Spoiler: OA

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Originally posted by CLIMBTHELADDER on 22 Apr 2018, 02:33.
Last edited by Bunuel on 22 Apr 2018, 02:38, edited 1 time in total.

Renamed the topic and edited the question.

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Re: The table above shows the number of employees at each of four salary [#permalink]

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22 Apr 2018, 02:50

IRONMANGMAT wrote:

Spoiler: ::

Attachment:

GAMT_PS_1205.png

weighted average problem

avg = $\frac{(20000*5 + 22000*4 + 25000*8 + 30000*3)}{20}$ = 23900

ans C
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Director

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Re: The table above shows the number of employees at each of four salary [#permalink]

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22 Apr 2018, 04:04

Remove zeros and add them later

Av=20*5 +22*4 +8*25 +30*3 /20
=23.9 multiply by 1000 =23900

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Re: The table above shows the number of employees at each of four salary [#permalink]

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16 Aug 2018, 01:49

Hi,
Simply assume that all get 20,000 then the average would have been 20,000.
Now 4 people get 2000 more than average, 8 people get 5000 more than average, 3 people get 10000 more than average
the total would be (4*2000)+(8*5000)+(3*10000)=78000
And this additional 78000 would be divided equally among 20 people

newavg= 20,000+(78000/20)
=20,000+3900
=23,900

Hence Option C

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Re: The table above shows the number of employees at each of four salary [#permalink]

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15 Sep 2019, 11:40

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