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The value of (2^5*3^2*5^2)^1/2 is between which of the follo

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The value of (2^5*3^2*5^2)^1/2 is between which of the follo  [#permalink]

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New post Updated on: 11 Oct 2013, 02:04
2
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00:00
A
B
C
D
E

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84% (01:01) correct 16% (01:05) wrong based on 229 sessions

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The value of \(\sqrt{2^5 * 3^2 * 5^2}\) is between which of the following pairs of numbers?

A. 0 and 100
B. 100 and 200
C. 200 and 300
D. 300 and 400
E. 400 and 500

Originally posted by tonebeeze on 11 Mar 2011, 10:49.
Last edited by Bunuel on 11 Oct 2013, 02:04, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Square Roots  [#permalink]

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New post 11 Mar 2011, 11:25
1
tonebeeze wrote:
The value of \(\sqrt{2^5 * 3^2 * 5^2}\) is between which of the following pairs of numbers?

a. 0 and 100
b. 100 and 200
c. 200 and 300
d. 300 and 400
e. 400 and 500


\(\sqrt{2^5 * 3^2 * 5^2}\) = \(\sqrt{2^4*2 * 3^2 * 5^2}\)

This reduces to \(2^2*3*5* \sqrt{2}\) = 60*1.414 \(\approx\) 96 so answer should be A
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Re: Square Roots  [#permalink]

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New post 11 Mar 2011, 12:31
beyondgmatscore wrote:
tonebeeze wrote:
The value of \(\sqrt{2^5 * 3^2 * 5^2}\) is between which of the following pairs of numbers?

a. 0 and 100
b. 100 and 200
c. 200 and 300
d. 300 and 400
e. 400 and 500


\(\sqrt{2^5 * 3^2 * 5^2}\) = \(\sqrt{2^4*2 * 3^2 * 5^2}\)

This reduces to \(2^2*3*5* \sqrt{2}\) = 60*1.414 \(\approx\) 96 so answer should be A


Agree!!! Just the 60*1.4 < 60*1.5 = 60*3/2 = 90.
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Re: The value of (2^5*3^2*5^2)^1/2 is between which of the follo  [#permalink]

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New post 12 Nov 2014, 23:48
\(\sqrt{2^5 * 3^2 * 5^2} = \sqrt{2} * 4 * 3 * 5 = 1.414 * 60\)

Answer = A
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Re: The value of (2^5*3^2*5^2)^1/2 is between which of the follo  [#permalink]

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New post 15 Jul 2019, 06:27
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Re: The value of (2^5*3^2*5^2)^1/2 is between which of the follo   [#permalink] 15 Jul 2019, 06:27

The value of (2^5*3^2*5^2)^1/2 is between which of the follo

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