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# The width of a rectangle w is twice the length of the rectangle. Which

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Joined: 02 Sep 2009
Posts: 56261
The width of a rectangle w is twice the length of the rectangle. Which  [#permalink]

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19 Aug 2018, 09:31
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35% (medium)

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57% (00:42) correct 43% (01:09) wrong based on 26 sessions

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The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?

(A) $$w$$

(B) $$2w^2$$

(C) $$3w^2$$

(D) $$\frac{w^2}{2}$$

(E) $$\frac{w^2}{4}$$

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Re: The width of a rectangle w is twice the length of the rectangle. Which  [#permalink]

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19 Aug 2018, 09:37
Bunuel wrote:
The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?

(A) $$w$$

(B) $$2w^2$$

(C) $$3w^2$$

(D) $$\frac{w^2}{2}$$

(E) $$\frac{w^2}{4}$$

w=2l
area=lw
area=w^2/2
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Posts: 1028
WE: Supply Chain Management (Energy and Utilities)
Re: The width of a rectangle w is twice the length of the rectangle. Which  [#permalink]

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19 Aug 2018, 09:39
Bunuel wrote:
The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?

(A) $$w$$

(B) $$2w^2$$

(C) $$3w^2$$

(D) $$\frac{w^2}{2}$$

(E) $$\frac{w^2}{4}$$

Given, w=2l or, l=w/2

Area of rectangle=l*w=(w/2)*w=$$\frac{w^2}{2}$$

Ans. (D)
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Re: The width of a rectangle w is twice the length of the rectangle. Which  [#permalink]

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19 Aug 2018, 10:01
Bunuel wrote:
The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?

(A) $$w$$

(B) $$2w^2$$

(C) $$3w^2$$

(D) $$\frac{w^2}{2}$$

(E) $$\frac{w^2}{4}$$

Given , width = $$w$$ & length is half of width . Hence length is = $$\frac{w}{2}$$
Hence area = $$w$$ *$$\frac{w}{2}$$ =$$\frac{w^2}{2}$$ Ans D
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Re: The width of a rectangle w is twice the length of the rectangle. Which   [#permalink] 19 Aug 2018, 10:01
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# The width of a rectangle w is twice the length of the rectangle. Which

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