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The width of a rectangle w is twice the length of the rectangle. Which

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The width of a rectangle w is twice the length of the rectangle. Which  [#permalink]

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New post 19 Aug 2018, 09:31
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A
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C
D
E

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Question Stats:

57% (00:42) correct 43% (01:09) wrong based on 26 sessions

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Re: The width of a rectangle w is twice the length of the rectangle. Which  [#permalink]

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New post 19 Aug 2018, 09:37
Bunuel wrote:
The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?


(A) \(w\)

(B) \(2w^2\)

(C) \(3w^2\)

(D) \(\frac{w^2}{2}\)

(E) \(\frac{w^2}{4}\)


w=2l
area=lw
area=w^2/2
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Re: The width of a rectangle w is twice the length of the rectangle. Which  [#permalink]

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New post 19 Aug 2018, 09:39
Bunuel wrote:
The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?


(A) \(w\)

(B) \(2w^2\)

(C) \(3w^2\)

(D) \(\frac{w^2}{2}\)

(E) \(\frac{w^2}{4}\)


Given, w=2l or, l=w/2

Area of rectangle=l*w=(w/2)*w=\(\frac{w^2}{2}\)

Ans. (D)
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Re: The width of a rectangle w is twice the length of the rectangle. Which  [#permalink]

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New post 19 Aug 2018, 10:01
Bunuel wrote:
The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?


(A) \(w\)

(B) \(2w^2\)

(C) \(3w^2\)

(D) \(\frac{w^2}{2}\)

(E) \(\frac{w^2}{4}\)


Given , width = \(w\) & length is half of width . Hence length is = \(\frac{w}{2}\)
Hence area = \(w\) *\(\frac{w}{2}\) =\(\frac{w^2}{2}\) Ans D
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Re: The width of a rectangle w is twice the length of the rectangle. Which   [#permalink] 19 Aug 2018, 10:01
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