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The width of a rectangle w is twice the length of the rectangle. Which
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30 Oct 2019, 02:30
30 Oct 2019, 02:30
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A
B
C
D
E
Difficulty:
15%
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Question Stats:
73% (00:48) correct
27%
(00:47)
wrong
based on 169
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The width of a rectangle w is twice the length of the rectangle. Which of the following equals the area of the rectangle in terms of w?
(A) \(w\)
(B) \(2w^2\)
(C) \(3w^2\)
(D) \(\frac{w^2}{2}\)
(E) \(\frac{w^2}{4}\)
(A) \(w\)
(B) \(2w^2\)
(C) \(3w^2\)
(D) \(\frac{w^2}{2}\)
(E) \(\frac{w^2}{4}\)
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Re: The width of a rectangle w is twice the length of the rectangle. Which
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30 Oct 2019, 04:51
30 Oct 2019, 04:51
Width = w
Length = width / 2 = w/2
Area = (w^2)/2
IMO D
Length = width / 2 = w/2
Area = (w^2)/2
IMO D
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Joined: 04 Jan 2015
Posts: 3723
Given Kudos: 165
Re: The width of a rectangle w is twice the length of the rectangle. Which
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31 Oct 2019, 06:06
31 Oct 2019, 06:06
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Solution
Given:
- • The width of a rectangle w is twice the length of the rectangle
To find:
- • Which of the following equals the area of the rectangle in terms of w
Approach and Working Out:
- • Length = \(\frac{w}{2}\)
• Width = w
• Therefore, area = \(\frac{w^2}{2}\)
Hence, the correct answer is Option D.
Answer: D
