Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 0911:00 AM PDT
-12:30 PM PDT
Welcome to the M7 MBA Spotlight Series, featuring MIT Sloan School of Management! This video is part of GMAT Club’s exclusive MBA Spotlight event, where top business schools meet prospective applicants like you.- Jun 30
08:00 AM PDT
-11:59 PM PDT
Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates! - Jul 10
11:00 AM PDT
-11:00 AM PDT
In our conversation, Kishore talks about how strategically he used data analytics to identify high impact areas to focus on as well as his early morning study routine (3 AM prep!) that optimized his GMAT preparation. 
Jul 1211:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Jul 1311:00 AM EDT
-12:30 PM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
12 Nov 2007, 20:40
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
77% (01:06) correct
23%
(01:22)
wrong
based on 1162
sessions
History
Date
Time
Result
Not Attempted Yet
The y intercept of a line L is 4. If the slope of L is negative, which of the following could be the x intercept of L.
I. -1
II. 0
III. 6
A. I only
B. II only
C. III only
D. I and II
E. I and III
I. -1
II. 0
III. 6
A. I only
B. II only
C. III only
D. I and II
E. I and III
Updated on: 03 Jul 2020, 08:06
Originally posted by BrentGMATPrepNow on 26 Aug 2016, 12:41.
Last edited by BrentGMATPrepNow on 03 Jul 2020, 08:06, edited 1 time in total.
Last edited by BrentGMATPrepNow on 03 Jul 2020, 08:06, edited 1 time in total.
Kudos
Bookmarks
Balvinder
The y intercept of a line L is 4. If the slope of L is negative, which of the following could be the x intercept of L.
I. -1
II. 0
III. 6
A. I only
B. II only
C. III only
D. I and II
E. I and III
I. -1
II. 0
III. 6
A. I only
B. II only
C. III only
D. I and II
E. I and III
Let's draw a bunch of lines with a negative slope AND have a y-intercept of 4 (ie, passes through the point (0,4))
We get:
As we can see, the x-intercept can have ANY POSITIVE value.
So, the x-intercept COULD be 6, but it could NOT be -1 or 0
Answer: C
12 Nov 2007, 20:50
Kudos
Bookmarks
C) III only
The y-intercept is 4. Therefore we have y=mx+4
It is given that the slope is negative. Therefore the line must go from top left to bottom right.
i.e: the x-intercept has to be positive. That itself rules out I & II.
If you choose to go with the options directly, here's an approach.
y=mx+4. For the x-intercept, y=0.
i.e. mx+4=0.
We know that the slope m is negative. Therefore, if x=-1 or x=0, the equation mx+4 =0 would never be satisfied.
If x=6, we have 6m+4=0. A value of m=-2/3 would satisfy this equation.
Hope this helps.
The y-intercept is 4. Therefore we have y=mx+4
It is given that the slope is negative. Therefore the line must go from top left to bottom right.
i.e: the x-intercept has to be positive. That itself rules out I & II.
If you choose to go with the options directly, here's an approach.
y=mx+4. For the x-intercept, y=0.
i.e. mx+4=0.
We know that the slope m is negative. Therefore, if x=-1 or x=0, the equation mx+4 =0 would never be satisfied.
If x=6, we have 6m+4=0. A value of m=-2/3 would satisfy this equation.
Hope this helps.
