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There are 12 coworkers who work on projects in teams. Each team is com

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Bunuel
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There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   19 Nov 2019, 23:44
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There are 12 coworkers who work on projects in teams. Each team is composed of 3 people. Each worker is on one and only one team. How many unique teams can be created?

(A) 4
(B) 12
(C) 220
(D) 660
(E) 1,320
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C
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   20 Nov 2019, 02:04
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Selecting 3 people at a time out of 12 people.......12c3=12!/9!*3!=220

OA:C
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   20 Nov 2019, 02:09
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12 workers can be divided in teams of 3

12c3 ways ; 220
IMO C

There are 12 coworkers who work on projects in teams. Each team is composed of 3 people. Each worker is on one and only one team. How many unique teams can be created?

(A) 4
(B) 12
(C) 220
(D) 660
(E) 1,320
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   20 Nov 2019, 05:00
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There are 12 coworkers who work on projects in teams. Each team is composed of 3 people. Each worker is on one and only one team. How many unique teams can be created?

(A) 4
(B) 12
(C) 220
(D) 660
(E) 1,320


12C3=220

Ans (C)
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   31 Jan 2020, 12:29
Can anyone explain the answer here ?
Why we are doing 12C3 only ?
What about the 4 groups formed of 3 people each ?
In that case will it not be 12C3 + 9C3 + 6C3 + 3C3 ?
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   19 Feb 2020, 17:49
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Rumsus wrote:
Can anyone explain the answer here ?
Why we are doing 12C3 only ?
What about the 4 groups formed of 3 people each ?
In that case will it not be 12C3 + 9C3 + 6C3 + 3C3 ?


Rumsus

Let's take 4 People and try to make teams of 2.

A B C D
AB
AC
AD
BC
BD
CD

Now try 4C2=6

I tried with 5 people and team of 3 I got the same result as 5C3. You can try that too. Let me know if you are unable to.

So what's happening is the moment you pick 2 people that's a team and we are counting it only once. And that's all that we want.

Hope that helps!
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There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   29 Jun 2021, 08:10
egmat MartyTargetTestPrep chetan2u VeritasKarishma ScottTargetTestPrep Bunuel
Shouldn't the answer to this question be 12C3*9C3*6C3/4! Since the question states how many "unique teams" can be made?
Curious to know why I'm wrong. Please let me know. Thank you
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   29 Jun 2021, 09:45
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Jainam24 wrote:
egmat MartyTargetTestPrep chetan2u VeritasKarishma ScottTargetTestPrep Bunuel
Shouldn't the answer to this question be 12C3*9C3*6C3/4! Since the question states how many "unique teams" can be made?
Curious to know why I'm wrong. Please let me know. Thank you



The question just asks to make unique teams of 3 persons.

What you are doing is finding different ways in which 12 people can be distributed in 4 teams of 3 person each.

12C3 would mean ABC, DEF, ABD and so on
Your answer means ABC-DEF-GHJ-KLM is one way and then ABD-CEF-GHJ-KLM is another one. Dividing by 4! means the order of the teams does not matter but you will still link 4 different teams to each other and a minor change between two teams will make the way a new one.
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   29 Jun 2021, 22:30
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Jainam24 wrote:
egmat MartyTargetTestPrep chetan2u VeritasKarishma ScottTargetTestPrep Bunuel
Shouldn't the answer to this question be 12C3*9C3*6C3/4! Since the question states how many "unique teams" can be made?
Curious to know why I'm wrong. Please let me know. Thank you


Had the question been "In how many distinct ways can you divide the 12 people into 4 teams of 3 people each?" then your answer would have been correct.
But the question is just asking "How many unique 3 people teams can you make from the 12 people?" so all you need to do is 12C3.
I agree that the question is set up in a way that makes you jump to the solution given by you but that is not what is asked eventually.
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   01 Jul 2021, 18:51
Okay now I got my mistake. Thanks a ton chetan2u and VeritasKarishma
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   12 Jul 2021, 00:06
VeritasKarishma wrote:
Jainam24 wrote:
egmat MartyTargetTestPrep chetan2u VeritasKarishma ScottTargetTestPrep Bunuel
Shouldn't the answer to this question be 12C3*9C3*6C3/4! Since the question states how many "unique teams" can be made?
Curious to know why I'm wrong. Please let me know. Thank you


Had the question been "In how many distinct ways can you divide the 12 people into 4 teams of 3 people each?" then your answer would have been correct.
But the question is just asking "How many unique 3 people teams can you make from the 12 people?" so all you need to do is 12C3.
I agree that the question is set up in a way that makes you jump to the solution given by you but that is not what is asked eventually.



Can you please tell me why we divided by 4! In this case?
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There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   12 Jul 2021, 00:12
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SushantSaini 4! was divided was there because all teams are identical. They aren't different. It is not like team A, B, C and D which makes them distinct.
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Re: There are 12 coworkers who work on projects in teams. Each team is com [#permalink] New post   15 May 2023, 19:39
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