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sherxon
Joined: 28 May 2021
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Location: Uzbekistan
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Schools: Carlson (A$$$) Kenan-Flagler '25 (A$$$$) Goizueta '25 (A$$$) Olin '25 (A$$$$) Fuqua '25 (M$$$$) Marshall '25 (A$$$$)
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03 Jun 2021, 05:52
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (02:20) correct
24%
(02:22)
wrong
based on 141
sessions
History
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There are an equal number of girls and boys in the summer camp. The number of boys under 13 years of age is twice as much as that of boys over 13. The total number of children in the camp is a4a, in which \(a\) is a digit. Find a.
A. 2
B. 4
C. 6
D. 7
E. 8
A. 2
B. 4
C. 6
D. 7
E. 8
03 Jun 2021, 07:26
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B is the answer.
444 can be divided as 222 total boys and further under 13 years age.
Rest numbers can not be divided.
Posted from my mobile device
444 can be divided as 222 total boys and further under 13 years age.
Rest numbers can not be divided.
Posted from my mobile device
04 Jun 2021, 01:52
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The number of boys = The number of girls.
Take option for a and form a4a. Divide number by 2 and get the number of boys.
The number of boys under 13 years of age is twice as much as that of boys over 13. This ratio is 2:1 [Total 2 + 1 = 3 parts]. So, the number of boys should be divisible by 3.
Only Option B = 4 satisfy condition 2.
=> 444 = 222 = 148 and 74.
Answer B
Take option for a and form a4a. Divide number by 2 and get the number of boys.
The number of boys under 13 years of age is twice as much as that of boys over 13. This ratio is 2:1 [Total 2 + 1 = 3 parts]. So, the number of boys should be divisible by 3.
Only Option B = 4 satisfy condition 2.
=> 444 = 222 = 148 and 74.
Answer B
