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The 5 subjects can be allotted to 6 periods in 6C5 = 6C1 = 6 ways. These 5 subjects can then be arranged in 5! = 120 ways.

The 6th period can be allotted any 1 subject in 5 ways.

Therefore the total number of ways = 6 * 120 * 5 = 3600 ways

Option E

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Bunuel
There are six periods in each working day of a school. Number of ways in which 5 subjects can be arranged if each subject is allotted at least one period and no period remains vacant is

(A) 210
(B) 360
(C) 1800
(D) 2100
(E) 3600



Solution:

If we let the five subjects be A, B, C, D, and E and let’s say A is repeated. So we can have, for example, ABCDEA for the six periods of the day. Of course, these six subjects (including the repeating subject A) can be arranged in 6! / 2! = 720/2 = 360 ways. However, since the repeating subject can be also B, C, D, or E, there are a total of 360 x 5 = 1800 ways to allot the 5 subjects for 6 periods without a vacant period.

Answer: C
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Why are there 5 options for the "?" slot? What in the question stem tells us one of the subjects must be repeated to fill this slot? Couldn't there simply be a 6th unknown subject?
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Why are there 5 options for the "?" slot? What in the question stem tells us one of the subjects must be repeated to fill this slot? Couldn't there simply be a 6th unknown subject?


That would be assuming information not presented in the question stem.

The question refers only to 5 subjects.

It is not an assumption to believe no other subjects exist.

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Bunuel
There are six periods in each working day of a school. Number of ways in which 5 subjects can be arranged if each subject is allotted at least one period and no period remains vacant is

(A) 210
(B) 360
(C) 1800
(D) 2100
(E) 3600



Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
There are 5 subjects and 6 periods. Each subject should be given one period at least.

So, only one slot remains vacant. That 1 slot can be filled by any of the 5 subjects.

Choose that one subject which is going to recur = 5C1 = 5

After choosing you will get the subjects as : ABCDE(A).

I have assumed the subjects to be A B C D E and the subject which is recurring as A .

Now arrange it = 6 periods can be arranged in 6! Ways

And a subject is recurring = 6!/2

Total ways = 5* (6!/2) = 5*6*5*4*3 = 25*4*6*3 = 100*18 = 1800

Option C
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hey there are 6 places and we need to fill everything at least one from the five so we can only do one subject 2 times. thus 6!divided by 2! to eliminate the common to get for one subject occurring twice gives 360 then multiply by 5 to get total 1800

Gknight5603
5c1*6c2*4*3*2*1= 1800 (C)

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