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Math Revolution GMAT Instructor
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There is a circle inscribed in a square, shown on the above figure. If
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23 Feb 2017, 20:28
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61% (01:01) correct 39% (00:57) wrong based on 139 sessions
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There is a circle inscribed in a square, shown on the above figure. If the length of the square is 2, what is the area of one of the 4 regions shaded? A. \(1π\) B. \(2π\) C. \(4π\) D. \(1(\frac{π}{2})\) E. \(1(\frac{π}{4})\)
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Re: There is a circle inscribed in a square, shown on the above figure. If
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23 Feb 2017, 20:38
MathRevolution wrote: Attachment: 1.png There is a circle inscribed in a square, shown on the above figure. If the length of the square is 2, what is the area of one of the 4 regions shaded? A. \(1π\) B. \(2π\) C. \(4π\) D. \(1(\frac{π}{2})\) E. \(1(\frac{π}{4})\) area of one of the 4 regions shaded = (area of Square  area of circle)/4 = (4pi)/4 = 1 pi/4 Hence Option E is correct Hit Kudos if you liked it



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Re: There is a circle inscribed in a square, shown on the above figure. If
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26 Feb 2017, 21:28
==> The area of the squarearea of the \(circle=2^2 π=4 π\), and since it asks for one of the 4 regions shaded, you get \(\frac{4 π}{4}=1(\frac{π}{4})\). The answer is E. Answer: E
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Re: There is a circle inscribed in a square, shown on the above figure. If
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08 Mar 2017, 22:13
Silly mistake but fixed it you have to multiply 1 by 1 to get the area of one fourth of the square and then subtract it by the area of the remaining portion of the circle inside it; though, you can just find the area of the circle and divide it by 4. Thus,
1 x 1= 1 pi (1)^2= pi (1) / 4
1 pi(1)/4



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Re: There is a circle inscribed in a square, shown on the above figure. If
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09 Mar 2017, 01:20
Side of square = diameter of circle = 2 x radius\therefore radius = diameter/2 = 1 Area of shaded region = area of square  area of circle = 2 x2  pi*1*1 = 4 pi Since there are 4 equal parts of the shaded region, area of one shaded region = (4 pi)/4 = 1  pi/4 Option E Hit kudos and visit our page for free GMAT prep articles : www.byjus.com/freegmatprep
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Re: There is a circle inscribed in a square, shown on the above figure. If
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29 Jan 2018, 20:23
Can someone please explain to me why the area of the circle isnt pi*radius^2? Why is it just pi?



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Re: There is a circle inscribed in a square, shown on the above figure. If
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29 Jan 2018, 21:04
teamryan15 wrote: Can someone please explain to me why the area of the circle isnt pi*radius^2? Why is it just pi? The area is \(pi*r^2\) itself but the length of square is 2, which is equal to diameter. Hence radius is 2/2=1 So r^2=1^2=1.. What is left is pi*r^2=pi*1^2=pi
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Re: There is a circle inscribed in a square, shown on the above figure. If
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01 Jun 2019, 23:19
MathRevolution wrote: Attachment: 1.png There is a circle inscribed in a square, shown on the above figure. If the length of the square is 2, what is the area of one of the 4 regions shaded? A. \(1π\) B. \(2π\) C. \(4π\) D. \(1(\frac{π}{2})\) E. \(1(\frac{π}{4})\) Square Area= 4 Diameter= 2, Radius= 1 Area of circle= PI. Now Total shaded region= 4PI 1/4 th of shaded region= (1/4) (4_PI) E
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Re: There is a circle inscribed in a square, shown on the above figure. If
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