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04 Mar 2025, 20:59
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Seniors: 58
Juniors: 20
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
71% (02:44) correct
29%
(03:14)
wrong
based on 804
sessions
History
Date
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Not Attempted Yet
There were 250 seniors and 200 juniors in an auditorium. While the 250 seniors and 200 juniors were in the auditorium, another group of students consisting of only juniors and seniors entered the auditorium. Once this new group of students entered the auditorium, the ratio of the number of seniors to the number of juniors in the auditorium was 7 to 5.
In the table, select a number of Seniors who entered the auditorium and a number of Juniors who entered the auditorium that are jointly consistent with the information given. Make only two selections, one in each column.
In the table, select a number of Seniors who entered the auditorium and a number of Juniors who entered the auditorium that are jointly consistent with the information given. Make only two selections, one in each column.
| Seniors | Juniors | |
| 20 | ||
| 25 | ||
| 28 | ||
| 35 | ||
| 58 | ||
| 87 |
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Official Answer
Seniors: 58
Juniors: 20
04 Mar 2025, 21:18
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Let say A seniors and B junior were added then new ratio would be: (250 + A) / (200 + B) = 7/5
Solving this would provide you with the equation: A = 30 + 1.4B;
Now, Check the options and get the answer.
Solving this would provide you with the equation: A = 30 + 1.4B;
Now, Check the options and get the answer.
04 Mar 2025, 21:40
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Before forming equations, we can simply put the values given in options for seniors or juniors and see whether they are divisible by 7 or 5 respectively, while doing this we get the value 58 for Seniors and 20 for juniors. 250+58 = 308 which is divisible by 7 with a multiplier of 44, and in turn multiply it with 5 we get 220, which is just 20 more juniors.
