What is the result of adding the units digit of 2002^2002 to the units

Question

What is the result of adding the units digit of 2002^2002 to the units digit of 7007^7007?

(A) 1
(B) 4
(C) 5
(D) 7
(E) 9

rajatchopra1994 · Answer

Explanation:

Using the concept of cyclicity;
2002^2002 = 2^2
= 4 
7007^7007 = 7^7 = 7^3
= 3

Unit Digit = 4+3 = 7

IMO-D

satya2029 · Answer

2002^4(500)+2
2^ 
unit digit=4
7007^7007
7^ 
7^4*7^3
unit digit=3
Sum=4+3
=7
D:)

Kinshook · Answer

Asked: What is the result of adding the units digit of 2002^2002 to the units digit of 7007^7007?

Unit digit of 2002^2002 = Unit digit of 2^2 = 4
Unit digit of 7007^7007 = Unit digit of 7^7 = 7^3 = 3

Unit digit of 2002^2002 + Unit digit of 7007^7007 = 4 + 3 = 7

IMO D

Neha2404 · Answer

IMO-D

2 and 7 both have 4n cyclicity

2002^2002= 2^2
 =4
(Here 2 equal to remainder 2002/4)
7007^7007. =7^3
 = 3 unit digit

(Here 3 equal to remainder when 7007/4)

Total of unit digit=4+3=7

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muhammaddk92 · Answer

,Units digits for squares of 2 are in order 2,4,6,8. 2000 goes into 4 500 times so 2 is left. Hence units digit for 2 will be 4 (which is the units digit for term 2002).

,Units digit for squares for 7 are in order 7,9,3,1. 7000 goes into 4 1750 times so 7 is left. 7th term is 3.

4+3=7

What is the result of adding the units digit of 2002^2002 to the units

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What is the result of adding the units digit of 2002^2002 to the units

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