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Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba

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Bunuel
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Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink] New post   08 Nov 2018, 00:20
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Three hungry children, Sharon, Carol, and Elinor, agree to divide a batch of cookies in the ratio 3 : 5 : 7, respectively. If Sharon’s share was 15 cookies, how many cookies were in that batch?

A. 60
B. 75
C. 120
D. 150
E. 750
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B
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Re: Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink] New post   08 Nov 2018, 00:29
S:C:E----- 3:5:7-----15:25:35
So total: 75
B.
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Re: Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink] New post   08 Nov 2018, 00:30
No of cookies with each be 3x,5x,7x.

Sharon has 15 cookies. So 3x = 15
x=5.

Total cookies are 15x = 75

Option: B

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Re: Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink] New post   08 Nov 2018, 03:03
Three hungry children, Sharon, Carol, and Elinor, agree to divide a batch of cookies in the ratio 3 : 5 : 7, respectively. If Sharon’s share was 15 cookies, how many cookies were in that batch?

A. 60
B. 75
C. 120
D. 150
E. 750

3+5+7=15

3x/15=15
x=75.. option B
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Re: Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink] New post   30 Nov 2020, 10:09
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Bunuel wrote:
Three hungry children, Sharon, Carol, and Elinor, agree to divide a batch of cookies in the ratio 3 : 5 : 7, respectively. If Sharon’s share was 15 cookies, how many cookies were in that batch?

A. 60
B. 75
C. 120
D. 150
E. 750

Solution:

We can let 3x, 5x, and 7x be the number of cookies that Sharon, Carol, and Elinor have, respectively. We can create the equation:

3x = 15

x = 5

Since the total number of cookies, in terms of x, is 3x + 5x + 7x = 15x, the total number of cookies is 15(5) = 75.

Answer: B
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Re: Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink] New post   30 Nov 2020, 10:12
Given: Three hungry children, Sharon, Carol, and Elinor, agree to divide a batch of cookies in the ratio 3 : 5 : 7, respectively.
Asked: If Sharon’s share was 15 cookies, how many cookies were in that batch?

Let Sharon, Carol, and Elinor have 3k, 5k & 7k cookies respectively

Since Sharon's share was 15 cookies
3k = 15
k = 5

Cookies in the batch = 3k + 5k + 7k = 15k = 15*5 = 75

IMO B
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Re: Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink] New post   30 Nov 2020, 10:58
Bunuel wrote:
Three hungry children, Sharon, Carol, and Elinor, agree to divide a batch of cookies in the ratio 3 : 5 : 7, respectively. If Sharon’s share was 15 cookies, how many cookies were in that batch?

A. 60
B. 75
C. 120
D. 150
E. 750

Sharon : Carol : Elinor = 3 : 5 : 7

Quote:
If Sharon’s share was 15 cookies, how many cookies were in that batch?


\(= \frac{15}{3}*(3+5+7)\)

\(= 75\), Answer must be (B)
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Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink] New post   30 Nov 2020, 21:12
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CONCEPT:Ratios
Equate the sum of the ratios to the total value if provided.
SOLUTION: Given the sum of all parts = 3+5+7 =15 parts
Given 3 parts = 15
=>1 part =5 cookies
Total or 15 parts =5*15=75 cookies (B)

Hope this helps :thumbsup:
Devmitra Sen
GMAT Club Bot
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Three hungry children, Sharon, Carol, and Elinor, agree to divide a ba [#permalink]
30 Nov 2020, 21:12
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