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09 Jan 2021, 02:16
Kudos
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (02:03) correct
23%
(01:27)
wrong
based on 80
sessions
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Three snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability that exactly one sniper missed?
A. 0.015
B. 0.185
C. 0.485
D. 0.515
E. 0.985
A. 0.015
B. 0.185
C. 0.485
D. 0.515
E. 0.985
The snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability:
1. that exactly one sniper missed?
2. that exactly one sniper hit?
3. that exactly two snipers missed?
4. that exactly two snipers hit?
1. that exactly one sniper missed?
2. that exactly one sniper hit?
3. that exactly two snipers missed?
4. that exactly two snipers hit?
09 Jan 2021, 03:01
Kudos
Bookmarks
Three snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability that exactly one sniper missed?
A= 0.9, B= 0.7 and C= 0.5
Total Probability= Only A miss + Only B miss+ Only C miss = (1-0.9)*0.7*0.5 + 0.9*(1-0.7)*0.5 + 0.9*0.7*(1-0.5)
= 0.035+0.135+0.315= 0.485
So, I think C.
A= 0.9, B= 0.7 and C= 0.5
Total Probability= Only A miss + Only B miss+ Only C miss = (1-0.9)*0.7*0.5 + 0.9*(1-0.7)*0.5 + 0.9*0.7*(1-0.5)
= 0.035+0.135+0.315= 0.485
So, I think C.
noobieTopro
GMAT 2: 700 Q49 V37
Posts: 46
09 Jan 2021, 04:20
Kudos
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TarunKumar1234
Three snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability that exactly one sniper missed?
A= 0.9, B= 0.7 and C= 0.5
Total Probability= Only A miss + Only B miss+ Only C miss = (1-0.9)*0.7*0.5 + 0.9*(1-0.7)*0.5 + 0.9*0.7*(1-0.5)
= 0.035+0.135+0.315= 0.485
So, I think C.
A= 0.9, B= 0.7 and C= 0.5
Total Probability= Only A miss + Only B miss+ Only C miss = (1-0.9)*0.7*0.5 + 0.9*(1-0.7)*0.5 + 0.9*0.7*(1-0.5)
= 0.035+0.135+0.315= 0.485
So, I think C.
Bunuel
Three snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability that exactly one sniper missed?
A. 0.015
B. 0.185
C. 0.485
D. 0.515
E. 0.985
A. 0.015
B. 0.185
C. 0.485
D. 0.515
E. 0.985
The snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability:
1. that exactly one sniper missed?
2. that exactly one sniper hit?
3. that exactly two snipers missed?
4. that exactly two snipers hit?
1. that exactly one sniper missed?
2. that exactly one sniper hit?
3. that exactly two snipers missed?
4. that exactly two snipers hit?
It is 'C' indeed.
Probability
Soldier 1 - hit-0.9 / miss-0.1
Soldier 2 - hit-0.7 / miss-0.3
Soldier 3 - hit-0.5 / miss-0.5
Probability that exactly one sniper missed -
(1) miss and (2)(3) hit = (0.1)(0.7)(0.5)
OR (+)
(2) miss and (1)(3) hit = (0.9)(0.3)(0.5)
OR (+)
(3) miss and (1)(2) hit = (0.9)(0.7)(0.5)
Answer = option C. 0.485
