Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
Updated on: 19 Apr 2012, 01:44
Originally posted by shadabkhaniet on 18 Apr 2012, 23:52.
Last edited by Bunuel on 19 Apr 2012, 01:44, edited 1 time in total.
Last edited by Bunuel on 19 Apr 2012, 01:44, edited 1 time in total.
Added the OA
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
46% (03:14) correct
54%
(03:18)
wrong
based on 438
sessions
History
Date
Time
Result
Not Attempted Yet
A new sales clerk in a department store has been assigned to mark sale items with red tags, and she has marked 30% of the store items for sale. However, 20% of the items that are supposed to be marked with their regular prices are now marked for sale, and 55% of the items that are supposed to be marked for sale are marked with regular prices. What percent of the items that are marked for sale are supposed to be marked with regular prices?
A. 30%
B. 35%
C. 40%
D. 45%
E. 50%
A. 30%
B. 35%
C. 40%
D. 45%
E. 50%
19 Apr 2012, 01:42
Kudos
Bookmarks
shadabkhaniet
# of items 100 (assume);
# of items that should be marked for sale is x;
# of items that should be at the regular price is 100-x;
# of items that are actually marked for sale 0.3*100=30.
Let's see how many items are marked for sale:
20% of 100-x (20% of the items that are supposed to be marked with their regular prices (100-x) are now marked for sale);
100-55=45% of x (since 55% of the items that are supposed to be marked for sale (x) are marked with regular prices, then the remaining 45% of x are marked for sale);
So, 0.2(100-x)+0.45x=30 --> x=40 (# of items that should be marked for sale).
So, # of the items that are supposed to be marked with their regular prices is 0.2*(100-40)=12, which is 12/30*100=40% of # of items that are actually marked for sale.
Answer: C.
27 Jul 2012, 10:53
Kudos
Bookmarks
Here is a pure algebraic approach:
If in the store there are \(R\) items that should sell at regular price, and \(S\) items that should sell at reduced price,
then the total number of items is \(R + S\).
\(30%\) of them, or \(0.3(R + S)\) items are now marked for sale and this is comprised of \(0.2R\) and \(0.45S\),
as wrongly \(20%\) of the regular items, and only \(45%\) of the sale items were marked for sale (\(55%\) of the sale items were marked regular).
So, \(0.3(R + S) = 0.2R + 0.45S\), from which we can deduce that \(0.1R = 0.15S\), or \(2R = 3S.\)
We have to evaluate the ratio \(\frac{0.2R}{0.3(R+S)}\) - out of those marked for sale, what fraction/percentage should be marked regular.
\(\frac{0.2R}{0.3(R+S)}=\frac{2R}{3R+3S}=\frac{2R}{3R+2R}=\frac{2R}{5R}=\frac{2}{5}=40%\).
Hence, answer C.
If in the store there are \(R\) items that should sell at regular price, and \(S\) items that should sell at reduced price,
then the total number of items is \(R + S\).
\(30%\) of them, or \(0.3(R + S)\) items are now marked for sale and this is comprised of \(0.2R\) and \(0.45S\),
as wrongly \(20%\) of the regular items, and only \(45%\) of the sale items were marked for sale (\(55%\) of the sale items were marked regular).
So, \(0.3(R + S) = 0.2R + 0.45S\), from which we can deduce that \(0.1R = 0.15S\), or \(2R = 3S.\)
We have to evaluate the ratio \(\frac{0.2R}{0.3(R+S)}\) - out of those marked for sale, what fraction/percentage should be marked regular.
\(\frac{0.2R}{0.3(R+S)}=\frac{2R}{3R+3S}=\frac{2R}{3R+2R}=\frac{2R}{5R}=\frac{2}{5}=40%\).
Hence, answer C.
