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chetan2u
Is \(\frac{|x|}{x} > \frac{|y|}{y}\)?

(1) \(x<0\)
(2) \(y<0\)


Self Made
slightly tricky
OA in two days
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chetan2u
Is \(\frac{|x|}{x} > \frac{|y|}{y}\)?

(1) \(x<0\)
(2) \(y<0\)


Self Made
slightly tricky
OA in two days

Is \(\frac{|x|}{x} > \frac{|y|}{y}\)?
Both left hand side and right hand side can have only two values 1 or -1. For a definitive 'yes' answer we need left hand side to be 1 and right hand side to be -1. In other words, we need \(x>0\) and \(y<0\). If \(x<0\) or if \(y>0\) then left hand side can never be greater than the right side. It can at best be equal to right hand side. Hence, if we know any of these then we will have a definitive 'no' answer.

Statement 1:
\(x<0\)
As mentioned above, this can at best be equal to right hand side (if \(y>0\)) but can never be greater. Hence, we have a definitive no answer.
This statement is sufficient and we can eliminate option B, C and E.

Statement 2:
\(y<0\).
We have not been given any information about \(x\). \(x\) can be both negative and positive.
As mentioned above, if \(x>0\) and \(y<0\) then we get a yes answer to the question.
However, if \(x<0\) and \(y<0\), then we get a no answer, (as both side will be equal to - 1)
Hence, this statement is insufficient. We can eliminate option D.

The correct answer is A.

chetan2u: Very nice question sir. Would it be better to mention \(xy\neq{0}\) in the question prompt. Probably I am wrong. I am new to this :)
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chetan2u
Is \(\frac{|x|}{x} > \frac{|y|}{y}\), if \(xy\neq{0}\) ?

(1) \(x<0\)
(2) \(y<0\)


Self Made
slightly tricky
OA in two days

Information given= xy is not equal to 0

question asked:- \(\frac{|x|}{x} > \frac{|y|}{y}\)

(1) \(x<0\)

That means X is -ve
\(\frac{|x|}{x} is -1(+ve/-ve = -ve)\\
\frac{|y|}{y}\) can either be 1 ot -1

\(\frac{|x|}{x} > \frac{|y|}{y}\) will never be possible in both the cases.


(2) \(y<0\)

Y is -ve

\(\frac{|x|}{x} > \frac{|y|}{y}\) can be possible when X is +ve but not possible when x is -ve.

A is the answer
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\(|x|/x > |y|/y\) ?

will be possible only if x is +ve and y is -ve

so question is x > 0 AND y < 0 ?

Statement 1: x < 0 => sufficient to answer the question, is x > 0 AND y < 0 ? as NO
Statement 2: y < 0 => insufficient to tell about sign of x

Answer (A)

Good question chetan2u
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|x|/x = 1 when x >0
= -1 when x<0
Similarly
|y|/y = 1 when y >0
= -1 when y<0


Statement 1: x<0
|x|/x = -1

|y|/y could be either 1 or -1
So |x|/x will never be greater than |y|/y

is |x|/x > |y|/y?
Answer is always NO.
So, statement 1 is sufficient to answer the question.


Statement 2: y<0
|y|/y = -1
|x|/x could be either 1 or -1
If |x|/x =1 and 1 > -1 so, |x|/x > |y|/y

If |x|/x =-1, then -1 is not greater than -1
so |x|/x is not greater than |y|/y

is |x|/x > |y|/y?
The answer could be Yes or No, considering both cases

Statement 2 is insufficient


Thanks,
CLIFIN J FRANCIS
GMAT SME
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