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so, there is no way to test whether both values of x in st2 will cause the ABS to have the same value?
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It took me almost 4 mins to solve for all the value of x and to plug them back in for testing.
Is there any faster way to do 700+ level algebra DS like this one? Is it worth to spend that much time on such a question, if you know you can get it right but you have to spend twice as much time as you are allowed?
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Quote:
Each statement will give us two solutions for x. We can then plug these two values of x in to the expression in the question, and if we get the same answer both times, the statement is sufficient, and if we get two different answers, the statement is not sufficient.
My approach is a bit time consuming, but it works!

Statement 1: it is easy: (x+9)(x-2)=0;
x = -9, 2
Substituting -9 and 2 one by one, we get 2 & 7/9 respectively.

Statement 1 is insufficient

Statement 2
We know GMAT! Generally there is some sync between the results of both the statements. Since all the coefficients are positive, x=2 cannot be a solution.
Thus, we need to substitute x=-9
x=-9 solves the equation.
x1 + x2 = -(b/a)
i.e. -9 + x = -(46/3)
or, x = -(46/3) + 27/3
or, x = -19/3

Solving the expression for x = -19/3, we get 2
We had already solved the expression for x=-9 in Statement 1. So we know that x=-9 gives 2 as well

Therefore, for either values, expression results in 2
Statement (2) is sufficient
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