Rusty with maths

Question

I have started with quants, and straight away went for Number properties MGMAT. I am able to grasp 60-70% of the content.

Is it the right approach?
Please guide and share source where I could practice Number properties specific questions?
My OG is on the way, may be once it is with me I will try questions there too.

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Raxit85 · Answer

You can use below link to practice more questions from the forum questions directory. https://gmatclub.com/forum/search.php?view=search_tags

Russ19 · Answer

Going through the Manhattan prep strategy guides to master concepts for quant seems an excellent way to start. Then, you can practice a specific chapter from OGs with the timer at the GMAT Club and see the solution of experts. The link below must help you to find particular types of problems from diverse sources:

https://gmatclub.com/forum/search.php?view=search_tags

toy9575 · Answer

Yes that is probably the right way .good luck on your prep journey

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sachin91 · Answer

Hi,

I am looking for a dedicated study buddy who is planning to take GMAT in July or August, and targeting a score of 750+.
If anyone is interested, please connect with me.

Thanks
Sachin

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AkankshaGMAT1989 · Answer

Hi  Bunuel  and  bb  sir,

I need your help to solve the following equation. It is part of a larger DS question.

|X| + X^2 = 2X

My solution is:

If assume cases here:
1. |X| = X
 then the equation becomes >>> X+X^2 =2X
=X^2 -X = 0

= X(X-1) = 0

2 possible values of X that are X=0 or X =1

Case 2: |X| = - X

now, LHS is -X + X^2

Should RHS also be -2X or it should remain +2X because the answer changes with this consideration.

Thanks in advance.

Bunuel · Answer

You are replacing |x| with -x, when x < 0, but why should you replace x with -x? So, the answer to your question is NO. |x| + x^2 = 2x When x < 0, then |x| = -x, and in this case we'd get -x + x^2 = 2x, which gives x = 0 or x = 3. Discard both solutions because neither 0 nor 3 is in the range we consider (x < 0). When x >= 0, then |x| = x, and in this case we'd get x + x^2 = 2x, which gives x = 0 or x = 1. Both solutions are valid because both 0 and 1 are in the range we consider (x >= 0). So, |x| + x^2 = 2x has two solutions only x = 0 or x = 1.

HoneyLemon · Answer

You are on a right track .

I would suggest to go-through the gmat club math book and ques from each topic from gmatclub to solidify your learning and application .

Rusty with maths

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