Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
31% (03:22) correct
69%
(02:59)
wrong
based on 167
sessions
History
Date
Time
Result
Not Attempted Yet
Two trains A and B start from two points P1 and P2 respectively at the same time and travel towards each other. The difference between their speed is 10 kmph and train A takes one hour more to cover the distance between P1 and P2 as compared to train B. Also by the time they meet, train B has covered 200/9 km more as compared to train A. What is the distance between P1 and P2?
A) 150
B) 200
C) 250
D) 300
E) Data insufficient
A) 150
B) 200
C) 250
D) 300
E) Data insufficient
01 Jun 2020, 19:53
Kudos
Bookmarks
Speed of train A = v
Time taken by train A = t
\(v*t = (v+10)(t-1)\)
\(10t - v= 10\)
\(10t-10 = v\).....(1)
Both train meet after = \(\frac{20}{9}\) hrs
\(v*\frac{20}{9} + (v+10)*\frac{20}{9} = vt\)
\(40v+200 = 9vt\).....(2)
From (1) and (2)
\(40t-40+20= 9t^2-9t\)
\(9t^2-49t+20\)
\((t-5)(9t-4)=0\)
t= 5
or t = 4/9(<20/9) Not possible
\(v= 10*5-10 = 40\)
Distance \(= 40*5=200\)Km
Time taken by train A = t
\(v*t = (v+10)(t-1)\)
\(10t - v= 10\)
\(10t-10 = v\).....(1)
Both train meet after = \(\frac{20}{9}\) hrs
\(v*\frac{20}{9} + (v+10)*\frac{20}{9} = vt\)
\(40v+200 = 9vt\).....(2)
From (1) and (2)
\(40t-40+20= 9t^2-9t\)
\(9t^2-49t+20\)
\((t-5)(9t-4)=0\)
t= 5
or t = 4/9(<20/9) Not possible
\(v= 10*5-10 = 40\)
Distance \(= 40*5=200\)Km
carpedeim
01 Jun 2020, 20:13
Kudos
Bookmarks
Let the distance between P1 and P2 = D km
Let A speed = x km/hr
B speed =x +10 km /hr
When they both move towards each other B covers 200/9 km extra and B's extra speed over A is 10km/hr
Therefore they have both travel 20/ 9 hrs before they meet.
Therefore
20/9×x +20/9×(x+10)=D ----(1)
Also
D/x- D/(x+10)=1
D=x(x+10)÷10
Putting this value in eq 1
9x^2-310x -2000=0
Solving x=40 km/hr
Therefore
D= 40×50÷10
=200 km
Posted from my mobile device
Let A speed = x km/hr
B speed =x +10 km /hr
When they both move towards each other B covers 200/9 km extra and B's extra speed over A is 10km/hr
Therefore they have both travel 20/ 9 hrs before they meet.
Therefore
20/9×x +20/9×(x+10)=D ----(1)
Also
D/x- D/(x+10)=1
D=x(x+10)÷10
Putting this value in eq 1
9x^2-310x -2000=0
Solving x=40 km/hr
Therefore
D= 40×50÷10
=200 km
Posted from my mobile device
