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X is not equal to Y.

\(\frac{1}{x-y} >xy\)

Option 1.

\(\frac{x}{y} >1\)
\(x>y\)

Let's take x=10, y =8 then Is \(\frac{1}{10-8} > 10*8\) Ans is No

Let's take x=.9 and y= .1 then Is \(\frac{1}{.9-.1} > .09\) Ans is Yes

We do not have certain answer. Eliminate option A, D

option 2.

\(x>y\) is similar to option 1. Eliminate option B.

combining option 1 and 2 doesn't give additional information, so eliminate option C.

Remaining Answer is E.
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Question: If x is not equal to y, is 1/x−y>xy?

STatement 1: x/y>1

i.e.x and y have same sign and lxl > lyl

CAse 1: x = 1.1 and y = 1, 1/x−y>xy
CAse 2: x = 3 and y = 2, 1/x−y<xy

NOT SUFFICIENT

STatement 2: x>y

CAse 1: x = 1.1 and y = 1, 1/x−y>xy
CAse 2: x = 3 and y = 2, 1/x−y<xy

NOT SUFFICIENT

COmbining the statements

CAse 1: x = 1.1 and y = 1, 1/x−y>xy
CAse 2: x = 3 and y = 2, 1/x−y<xy

NOT SUFFICIENT

Answer: Option E
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IMO Anser Choice E

Statement1 :
Now when x>y two acses are possible
Case 1a : both x and y >1. Note that x is also positive since it is greatre than y and y itself is positive
Here the question stem will never hold true
Case 1 b: Both X and Y > 0 but less than 1 . In this case the question stem will hld true

Since We have already found Insufficiency with Statement 1 we are not dealing with Case 2 which itself has few subcases

Statement 2:
X>y . here Case 1a and case 1 b from statement 1 be referred(since the condition is same) to prove insufficiency of statememt 2

Combining 1 +2
Case 1a and Case 1b both hold true . Thus INSUFFICIENT
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Is a Yes or No question, plug numbers in different scenarios to find out

(1) Positives numbers higher than 1: If x=2 and y=1 then 1>2, so the answer is no.
Positives numbers higher between 0 and 1: If x=1/2 and y=1/4 then 4>1/8, so the answer is yes.
Two different answers so not sufficient.

(2) Here happens the same, if x=2 and y=1 then 1>2, so the answer is no and if x=1/2 and y=1/4 then 4>1/8, the answer is yes.
Two different answers so not sufficient.

(1) and (2) still not sufficient.
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Bunuel
If x is not equal to y, is \(\frac{1}{x - y} > xy\)?

(1) \(\frac{x}{y }> 1\)
let x= 4 and y=2 then no

when x=1 , y=1/2 , yes

Clearly insufficient

(2) \(x > y\)
Similar line of reasoning as A

Even when 1 and 2 is combined we can use similar reasoning therefore IMO E
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