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\(y = kx + 3\)
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
(A) 34
(B) 31
(C) 14
(D) 11
(E) 7
_________________
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
(A) 34
(B) 31
(C) 14
(D) 11
(E) 7
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SOLUTION
y = kx + 3
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
(A) 34
(B) 31
(C) 14
(D) 11
(E) 7
Since if \(y = 17\) when \(x = 2\), then \(17 = 2k + 3\) --> \(k=7\).
Thus, \(y = 7x + 3\). When \(x=4\), \(y = 7*4 + 3=31\).
Answer: B.
_________________
y = kx + 3
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
(A) 34
(B) 31
(C) 14
(D) 11
(E) 7
Since if \(y = 17\) when \(x = 2\), then \(17 = 2k + 3\) --> \(k=7\).
Thus, \(y = 7x + 3\). When \(x=4\), \(y = 7*4 + 3=31\).
Answer: B.
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\(y = kx + 3\) is the equation of the slope but in this context the question is different
\(y = K * 2 + 3\)to have y = 17 then K must be 7
\(17 = 7*2 + 3\)
\(y = 7*4 + 3\) ---> \(y = 31\)
B must be the answer. Sub 600
Thanks
_________________
\(y = K * 2 + 3\)to have y = 17 then K must be 7
\(17 = 7*2 + 3\)
\(y = 7*4 + 3\) ---> \(y = 31\)
B must be the answer. Sub 600
Thanks
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Answer is B.
Same explanation as Carcass's
Same explanation as Carcass's
Answer is B (=31)
Explanation is same as provided by Carcass above.
Explanation is same as provided by Carcass above.
Posts: 62
1) Put y =17 and x=2 and solve for K
2) Knowing k=7 from above and x=4 solve for Y ------> Y=31
Answer is B
2) Knowing k=7 from above and x=4 solve for Y ------> Y=31
Answer is B
bhavinshah5685
Joined: 25 Jun 2012
Last visit: 19 Jun 2017
Posts: 48
Location: India
WE:General Management (Energy)
Posts: 48
1 st step : solve given eqn for K by putting values of x and y. u get k=7
snd step : now put banck value of k=7 and x=4 in given eqn and solve for y.
you get y=31
so Y=31 answer
snd step : now put banck value of k=7 and x=4 in given eqn and solve for y.
you get y=31
so Y=31 answer
mbaiseasy
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Schools: Full Time MBA (A$)
Posts: 316
y = kx + 3
17 = k(2) + 3 --> 14 = 2k --> k=7
y = (7)(4) + 3 --> y = 31
Answer: B
17 = k(2) + 3 --> 14 = 2k --> k=7
y = (7)(4) + 3 --> y = 31
Answer: B
Posts: 62
Bunuel
given
y=kx+3
y=17 ; x=2
k = 4.
y=? if x = 7
y=31
JeffTargetTestPrep
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Expert reply
Posts: 2,973
Bunuel
We are given the equation y = kx + 3, where k is a constant.
We are also given that y = 17 when x = 2, so we can plug these values into the equation to first determine a value for k.
y = kx + 3
17 = 2k + 3
14 = 2k
k = 7
We now can determine the value of y when x = 4:
y = kx + 3
y = (7)(4) + 3
y = 28 + 3
y = 31
The answer is B.
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Bunuel
Given: y = kx + 3
Putting values of y and x.
17 = 2k+3; 2k = 14; k = 7.
Once k is known, I can calculate y for any value of x.
y = kx + 3
= {(7) * 4} +3
= 31
B is the answer
The approach is right as seen above.
But I doubt that this question is a 600 difficulty question.
Maybe sub-600 more obviously.
But I doubt that this question is a 600 difficulty question.
Maybe sub-600 more obviously.
y = kx + 3
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
(A) 34
(B) 31
(C) 14
(D) 11
(E) 7
May as well to use such approach:
If y = 17 when x = 2 -> 17 = 2k+3
When x = 4, y = 4k+3 = 2*(2k+3)-3=2*17-3=31
The answer is B.
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
(A) 34
(B) 31
(C) 14
(D) 11
(E) 7
May as well to use such approach:
If y = 17 when x = 2 -> 17 = 2k+3
When x = 4, y = 4k+3 = 2*(2k+3)-3=2*17-3=31
The answer is B.
My approach inspired by a video I saw on GMATPrepNow was pretty quick.
I saw the y intercept in the equation "y = kx + 3" = 3 which implies coordinate (0,3)
Then the question gave away another coordinate (2,17) which shows that there was a 14 point rise in y with a 2 point run in x
Hence, another 2 point run in x makes x=4 and y=17+14=31
I saw the y intercept in the equation "y = kx + 3" = 3 which implies coordinate (0,3)
Then the question gave away another coordinate (2,17) which shows that there was a 14 point rise in y with a 2 point run in x
Hence, another 2 point run in x makes x=4 and y=17+14=31
y = kx + 3
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
17=2K+3
K=14/2=7
y=7*4+3=31
In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ?
17=2K+3
K=14/2=7
y=7*4+3=31
Abhishek009
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Last visit: 17 Dec 2025
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Posts: 5,878
Bunuel
\(y = kx + 3\)
Substitute \(y = 17\) & \(x = 2\) in the above equation
Or, \(17 = k*2 + 3\)
Or, \(2k = 14\)
Or, \(k = 7\)
Quote:
Substitute x = 4 in the equation \(y = kx + 3\)
Or, \(y = 7*4 + 3\)
So, \(y = 31\), Answer must be (B)
_________________
Posts: 67
\(y=kx+3\)
\(17=2k+3\)
\(k=7\)
now
\(y=4*7+3\)
\(y=31\)
\(17=2k+3\)
\(k=7\)
now
\(y=4*7+3\)
\(y=31\)
Kinshook
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Joined: 03 Jun 2019
Last visit: 15 Sep 2026
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Schools: HBS '28 CBS '26 Wharton '26
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
Bunuel
y=kx+3
17 = 2k +3
k= 7
y = 4*7+3=28+3=31
IMO B
Posted from my mobile device
Hey guys!
I must have not seen here any explanation from the equity.
Look closer, if 2k and 4k are similar with the coefficient 2, i.e. 2*2k, it means that all equation might be similar multiplied by 2. So we understand that y must be doubled and 3 points less (because there is a sum on the right): 17*2-3 = 31. Easier, quicker and logical.
What do you think?
I must have not seen here any explanation from the equity.
Look closer, if 2k and 4k are similar with the coefficient 2, i.e. 2*2k, it means that all equation might be similar multiplied by 2. So we understand that y must be doubled and 3 points less (because there is a sum on the right): 17*2-3 = 31. Easier, quicker and logical.
What do you think?
Posts: 54
y=kx+3
then 17=2k+3
17-3= 2k
14=2k both divided by 2 then k=7 therefore
when x=4
y=7*4+3 /c k is constant
y=31 the answer is B
then 17=2k+3
17-3= 2k
14=2k both divided by 2 then k=7 therefore
when x=4
y=7*4+3 /c k is constant
y=31 the answer is B
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