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3^6-1 = (3^3)^2 -1 = (27^2)-1

Dividing (27^2)-1 by 13 will give us a reminder of 0 ( Hint: (2*13+1)^2-1/13 = (Reminder 1)-1=0

Hence the greatest prime factor must be 13.

/SW
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\(3^6 - 1\)

\(= 9^3 - 1^3\)

\(= (9-1)(9^2 + 9 + 1)\)

\(= 8 * 91\)

\(= 8 * 13 * 7\)

Answer = D = 13
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hi i think a simpler and easier method could be..
3^6-1=3^6-1^6 = (3^3-1)(3^3+1)
=26*28... clearly 13 is the ans
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Using the identity A^2 - B^2 = A+B x A-B
we get 28 x 26 => 13 hence D
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rrsnathan
What is the greatest prime factor of 3^6 - 1 ?

A. 2
B. 3
C. 7
D. 13
E. 17
It seems it does not have any pattern. The greatest prime factor changes randomly as the power increases.
So, I found the value of the expression and prime factored. That gives 13.
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Mathivanan Palraj
rrsnathan
What is the greatest prime factor of 3^6 - 1 ?

A. 2
B. 3
C. 7
D. 13
E. 17
It seems it does not have any pattern. The greatest prime factor changes randomly as the power increases.
So, I found the value of the expression and prime factored. That gives 13.

Using the identity will be way easier here ..!!
regards
Stone Cold
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\(3^{6}\) - \(1\) = \(729\) - \(1\)
= \(728\)
prime factors of \(728\) =\(2^{3}\) * \(7\) * \(13\)
greatest prime factor is 13
Correct answer - D
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rrsnathan
What is the greatest prime factor of 3^6 - 1 ?

A. 2
B. 3
C. 7
D. 13
E. 17

3^6 - 1 is a difference of squares, since 3^6 = (3³)² and 1 = 1²

So, we get: 3^6 - 1 = (3³ + 1)(3³ - 1)
= (27 + 1)(27 - 1)
= (28)(26)
= (2)(2)(7)(2)(13)

The prime factors are 2, 7 and 13
The greatest value is 13

Answer: D
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3^6 - 1

Using a² - b²= (a-b)(a+b)


3^6 - 1 = 3^6 - 1^6 = (3³ – 1³) (3³ + 1³)= (27-1)(27+1)=26x28=2x13x2x2x7

therefore greatest prime factor = 13

Hence D
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