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Question Stats:
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Which of the following functions does not intersect with y = 3x^2 + 2x + 1
A. y = 3x^2 + 3x + 1
B. y = 2x^2 + 3x + 1
C. y = 3x^2 + 2x + 3
D. y = 4x^2 + 2x - 3
E. y = x^2 + 2x + 3
A. y = 3x^2 + 3x + 1
B. y = 2x^2 + 3x + 1
C. y = 3x^2 + 2x + 3
D. y = 4x^2 + 2x - 3
E. y = x^2 + 2x + 3
This question is not from the OG, but I am stuck on this question. Can anyone help me? 
imsahlahno
Joined: 15 Sep 2013
Last visit: 14 Apr 2019
Posts: 27
Given Kudos: 26
Concentration: Strategy, Entrepreneurship
Schools: Anderson '18 Darden '18 Johnson '18 ISB '17 Kellogg '18 NUS '18 Haas '18 McCombs '18 (WL) Ross '18 (II)
GMAT 1: 680 Q47 V36
GMAT 2: 740 Q50 V40
GPA: 3.65
Products:
Schools: Anderson '18 Darden '18 Johnson '18 ISB '17 Kellogg '18 NUS '18 Haas '18 McCombs '18 (WL) Ross '18 (II)
GMAT 2: 740 Q50 V40
Posts: 27
04 Oct 2014, 03:34
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jkim1118
If you are familiar with graphs, this question gets solved within a minute as shown by Bunuel... but I am not that comfortable with graphs...
I solved it by equating the the equation given in the question stem to the equation given in the answer choices...
A. y = 3x^2 + 3x + 1 = 3x^2 + 2x + 1.. this gives x=0 thus these two sets of equations intersect at x=0 and y=1
B. y = 2x^2 + 3x + 1 = 3x^2 + 2x + 1... this gives x^2 -x = 0 which means either x=0 or x=1. Thus these two intersect at 2 points.
C. y = 3x^2 + 2x + 3 = 3x^2 + 2x + 1.. this does not give a solution... thus the answer is C
29 Oct 2015, 01:00
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Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.
Which of the following functions does not intersect with y = 3x^2 + 2x + 1
A. y = 3x^2 + 3x + 1
B. y = 2x^2 + 3x + 1
C. y = 3x^2 + 2x + 3
D. y = 4x^2 + 2x - 3
E. y = x^2 + 2x + 3
Let’s find the actual intersecting point of given function and each choice.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.
So only choice (C) has no intersecting point. The answer is (C).
Which of the following functions does not intersect with y = 3x^2 + 2x + 1
A. y = 3x^2 + 3x + 1
B. y = 2x^2 + 3x + 1
C. y = 3x^2 + 2x + 3
D. y = 4x^2 + 2x - 3
E. y = x^2 + 2x + 3
Let’s find the actual intersecting point of given function and each choice.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.
So only choice (C) has no intersecting point. The answer is (C).
