If you are familiar with graphs, this question gets solved within a minute as shown by Bunuel... but I am not that comfortable with graphs...
I solved it by equating the the equation given in the question stem to the equation given in the answer choices...
A. y = 3x^2 + 3x + 1 = 3x^2 + 2x + 1.. this gives x=0 thus these two sets of equations intersect at x=0 and y=1
B. y = 2x^2 + 3x + 1 = 3x^2 + 2x + 1... this gives x^2 -x = 0 which means either x=0 or x=1. Thus these two intersect at 2 points.
C. y = 3x^2 + 2x + 3 = 3x^2 + 2x + 1.. this does not give a solution... thus the answer is C
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Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.



Which of the following functions does not intersect with y = 3x^2 + 2x + 1

A. y = 3x^2 + 3x + 1
B. y = 2x^2 + 3x + 1
C. y = 3x^2 + 2x + 3
D. y = 4x^2 + 2x - 3
E. y = x^2 + 2x + 3


Let’s find the actual intersecting point of given function and each choice.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.

So only choice (C) has no intersecting point. The answer is (C).
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Hello Moderators,

The Tag for this question says this is an OG question. However, the comment from the poster says that it is not an OG question. Can you please confirm if this is actually an OG question, please?

I took too much time to solve this question. If this is an OG question, I need to practice more and find better ways of approaching these type of question

Thanks in advance.
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let's "plug-in" each answer one by one. Only choice (C) has no intersecting point => answer C

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