The graph of y = 3x^2 + 2x + 3 (option C) gives the same parabola as y = 3x^2 + 2x + 1, just shifted 2 units up. So, they won't intersect:

Answer: C.

Similar question to practice: the-line-represented-by-which-of-the-following-equation-does-137828.html
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Which of the following functions does not intersect with y = 3x^2 + 2x + 1

A. y = 3x^2 + 3x + 1
B. y = 2x^2 + 3x + 1
C. y = 3x^2 + 2x + 3
D. y = 4x^2 + 2x - 3
E. y = x^2 + 2x + 3


Let’s find the actual intersecting point of given function and each choice.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.

So only choice (C) has no intersecting point. The answer is (C).
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Hello Moderators,

The Tag for this question says this is an OG question. However, the comment from the poster says that it is not an OG question. Can you please confirm if this is actually an OG question, please?

I took too much time to solve this question. If this is an OG question, I need to practice more and find better ways of approaching these type of question

Thanks in advance.
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let's "plug-in" each answer one by one. Only choice (C) has no intersecting point => answer C

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