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Could you please explain this part 3600∗[10][/1000]=36 kmh
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Could you please explain this part 3600∗[10][/1000]=36 kmh


Hi...
You have to convert m into km and sec into h...
So 10m/s
1m= 1/1000 km ..... 10m=10/1000
1hour=60minutes..
And 1minute=60sec, so 1h =60*60 sec=3600sec
Therefore 1sec=1/3600 h...
Substitute in 10m/s....
(10/1000)/(1/3600)=3600*10/1000 kmph..
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I think this is a high-quality question and I agree with explanation.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I think this is a high-quality question and I don't agree with the explanation. Hi! When I was solving the question, for the average in the second half of the race, I considered the total distance and total time as I thought it meant at the time of the second half, the runner would have covered total dist and more time. Just wanted to understand how I can make sure I read the question right here- how do I know if it means for the second half ONLY vs for the second half. Sorry if this is very convoluted!
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I think this is a high-quality question and I don't agree with the explanation. Hi! When I was solving the question, for the average in the second half of the race, I considered the total distance and total time as I thought it meant at the time of the second half, the runner would have covered total dist and more time. Just wanted to understand how I can make sure I read the question right here- how do I know if it means for the second half ONLY vs for the second half. Sorry if this is very convoluted!

In the question, "the second half" refers only to that specific part of the race, the second 100 meters, not the whole race up to that point.
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I like the solution - it’s helpful.
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