Bunuel
What is the value of n?
(1) 36n ≥ n^2 + 324
(2) 325 > n^2 > 323
Kudos for a correct solution.
The OA will be revealed on Sunday VERITAS PREP OFFICIAL SOLUTION:A. You should immediately recognize the familiar symptoms of a quadratic equation in statement 1, even if it's a "quadratic inequality or equation." If you arrange that statement to look like a quadratic so that you can factor, you'll find:
0≥n^2−36n+324
Which factors to:
0≥(n−18)^2
And here's where you need to think strategically and logically - the only way for 0 to be "greater than or equal to" anything squared is for that squared term to be 0, as nothing squared can be negative. So this statement, while it may not immediately look like it, guarantees that (n−18)=0, so n=18. Statement 1 is sufficient.
Statement 2 is not sufficient, as it allows for multiple noninteger values of n, so the answer is A.
One big lesson from this problem - Data Sufficiency questions are written very precisely; had "greater than or equal to" been "less than or equal to" statement 1 would not have been close to sufficient. Precision-in-language (and symbology) matters!!